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Top Forums Shell Programming and Scripting Strange function call in the shell script parse_prog_args $@ Post 302996398 by digioleg54 on Tuesday 25th of April 2017 02:46:58 PM
Old 04-25-2017
Strange function call in the shell script parse_prog_args $@

I am converting shell script to Perl. In shell I have a code
Code:
 parse_prog_args()
{
  if [ $# -gt 0 ]
  then
    while [ ! -z "$1" ]
    do
      case $1 in
  -P* | -p* )
  export PROCESS_DATE=$2
  export MM=`echo $2 | cut -c5-6`
  export DD=`echo $2 | cut -c7-8`
  export YY=`echo $2 | cut -c3-4`
  export YYYY=`echo $2 | cut -c1-4`
  export PROCESS_DATE_US_MMDDYY="$MM/$DD/$YY"
  shift
  ;;
  -F* | -f* )
  export _REPORT_NAME_=$2
  export _REPORT_NAME_
  shift
  ;;
  -S* | -s* )
  export _SRC_DIR_=$2
  export _SRC_DIR_
  shift
  ;;
  -COPYONLY | -copyonly )
  export _COPY_ONLY_="1"
  export _COPY_ONLY_
  ;;
        *)
        echo "[$1] Argument is invalid"
        echo "Usage:"
        echo "\t$PROG"
        echo "\t\t[-S source_directory]    # provide bps batch job seq. 576 is default"
        echo "\t\t[-F cool_file_name]      # test extraction of price file without sending to ADP"
        echo "\t\t[-P process_date]        # provide bps batch job seq. 576 is default"
        echo "\t\t[-COPYONLY]              # provide bps batch job seq. 576 is default"
        exit
        ;;
      esac
      shift
    done
  fi
}
 parse_prog_args $@

What I don't understand is, why shell require such function call
Code:
 parse_prog_args $@

What it sends to the function?

Thanks for contribution
This User Gave Thanks to digioleg54 For This Post:
 

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