04-23-2017
Date/Time parts to variable as integer
Hi Guys,
i guess there is a several ways to grub the strings from date and time
like THISMONTH='/bin/date +%m'
but the hard part is to add or sub that string to a variable
i tried to use let command
TWOMONTHSAGO=$THISMONTH
declare -i TWOMONTHSAGO
let TWOMONTHSAGO-=2
but there are errors , syntax is wrong or it try to add string to integer...
i tried TWOMONTHSAGO = TWOMONTHSAGO-2
i'm a programmer but i'm not familiar with the bash script
can anybody help?
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hello,
I am in following situation.-
COUNT=`ls -l | wc -l`
echo $COUNT
---> 26
NO_OF_FILES=$COUNT-1
echo $NO_OF_FILES
---> 26-1
Here, I want the output to be 25. How could I do this. It seems simple, but I am not getting it. Please help me. (2 Replies)
Discussion started by: The Observer
2 Replies
2. UNIX for Advanced & Expert Users
I have a script in a directory and want to search the directory before like follows:
i=0
for file in ../HN_*
do
echo $file
((i+=1))
echo $i
done
Currently I get following output:
../HN_2
1
../HN_3
2 (2 Replies)
Discussion started by: ABE2202
2 Replies
3. Shell Programming and Scripting
Dear Unix experts
I want to define a variable which contains dynmic and static part, daynamic part is the first field.
Sample of data
dddd aaaa sssss 12345
ssss 2323 234234 4242
dddd 3223 34234 54353
ssss 24234 3434 42342
dddd rwrw 423423 werwer
nawk 'BEGIN {FS=" "}{... (4 Replies)
Discussion started by: yahyaaa
4 Replies
4. Emergency UNIX and Linux Support
Dear Unix experts
Moved from "Shell Programming and Scripting "
I want to define a variable which contains dynmic and static part, daynamic part is the first field.
Sample of data
dddd aaaa sssss 12345
ssss 2323 234234 4242
dddd 3223 34234 54353
ssss 24234 3434 42342
dddd rwrw 423423... (2 Replies)
Discussion started by: yahyaaa
2 Replies
5. Solaris
hello,
i am writing a script that takes the UID from the PASSWD and then i want
to increse the Number by one. for the Next user.
i cannot get this to work that a variable is as interger
example:
set i = 0
set $i = $+1
it's in tcsh if it's mather (10 Replies)
Discussion started by: shatztal
10 Replies
6. UNIX for Dummies Questions & Answers
So, the beginning of my script will cat & grep a file with the output directed to a new file. The data I have in this file needs to be parsed, read and evaluated.
Basically, I need to identify the latest date/time stamp and then calculate whether or not it is within 15 minutes of the current... (1 Reply)
Discussion started by: hynesward
1 Replies
7. Shell Programming and Scripting
I have number in file which contains date and serial number:
2013101000.
The last two digits are serial number (00). So maximum of serial number is 100.
After reaching 100 it becomes 00 with incrementing 10 which is day with max 31.
after reaching 31 it becomes 00 and increments 10... (31 Replies)
Discussion started by: Natalie
31 Replies
8. Shell Programming and Scripting
Dear community,
i got a problem to get "date +%j" as the right value.
Today is the 10th day of the year.
#./script.sh 2
#!/bin/bash/
Var1=$(date +%j)
Var2=$1
let result=$Var1+$Var2
echo $Var1 plus $Var2 equals $result
The output of the script is:
010 plus 2 equals 10... (9 Replies)
Discussion started by: OskarHF
9 Replies
9. Shell Programming and Scripting
Dear Perl users/experts,
Could somebody help me how to solve my problem, I have a hash variable that I want to convert into dot file (graphviz).
I know how to convert it to dot file but I need some modification on the output of the hash variable before convert it to dot file.
Eeach key of... (1 Reply)
Discussion started by: askari
1 Replies
10. Shell Programming and Scripting
Hello,
How can we convert date like format 20181004171050 in seconds ?
I can able to convert till date but failing for HHMMSS.
date -d "20181004" "+%s" output as 1538596800 .
But when i add hhmmss it is failing date -d "20181004172000" "+%s" result Invalid date
Kindly guide.
Regards (16 Replies)
Discussion started by: sadique.manzar
16 Replies
LEARN ABOUT DEBIAN
sttime
sttime(3) ShapeTools Toolkit Library sttime(3)
NAME
stMktime, stWriteTime - date and time handling
SYNOPSIS
#include <config.h>
#include <sttk.h.h>
time_tstMktime (char *string);
char*stWriteTime (time_t date);
DESCRIPTION
stMktime scans the given string and tries to read a date and time from it. It understands various formats of date strings. The following is
a list of all valid formats, optional parts in brackets.
[Tue] Jan 5[,] [19]93
This includes the standard asctime(3) format.
Jan 5 With no year given, the year defaults to the current year.
[19]93/01/05 This notation requires month and day represented by exactly two digits.
5.1.[19]93 This is the usual German notation.
5.1. German notation referencing the current year.
A certain time, given together with the date must always have the following form.
hours:minutes[:seconds]
Each of the fields must be an integer value within the proper range (hours: 0-23, minutes and seconds: 0-59). Values below
10 may be written as one digit numbers.
The time value may be placed anywhere in the date string: at the beginning, at the end, or somewhere in the middle. Any amount of white-
space may be given between a field of the time value and the separating colon. The time is always considered to be local time.
stWriteTime generates a time string similar to asctime(3) from its date argument.
SEE ALSO
asctime(3)
BUGS
Time Zone Names within the time string (like `MET') are not handled properly. In most cases they will cause a failure.
sttk-1.7 Thu Jun 24 17:43:35 1993 sttime(3)