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Top Forums Shell Programming and Scripting How to print lines that have values in certain columns ? Post 302995917 by Don Cragun on Friday 14th of April 2017 08:18:34 PM
Old 04-14-2017
That will work with some versions of awk and give you a syntax error with other versions of awk. The following should work with almost any version of awk:
Code:
awk '{$1=$1; print>("file"NF)}' dataset_1.txt

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PR(1)							      General Commands Manual							     PR(1)

NAME
pr - print file SYNOPSIS
pr [ option ... ] [ file ... ] DESCRIPTION
Pr produces a printed listing of one or more files on its standard output. The output is separated into pages headed by a date, the name of the file or a specified header, and the page number. With no file arguments, pr prints its standard input. Options apply to all following files but may be reset between files: -n Produce n-column output. +n Begin printing with page n. -b Balance columns on last page, in case of multi-column output. -d Double space. -en Set the tab stops for input text every n spaces. -h Take the next argument as a page header (file by default). -in Replace sequences of blanks in the output by tabs, using tab stops set every n spaces. -f Use formfeeds to separate pages. -ln Take the length of the page to be n lines instead of the default 66. -m Print all files simultaneously, each in one column. -n Number the lines of each file. -on Offset the left margin n character positions. -sc Separate columns by the single character c instead of aligning them with white space. A missing c is taken to be a tab. -t Do not print the 5-line header or the 5-line trailer normally supplied for each page. -wn For multi-column output, take the width of the page to be n characters instead of the default 72. SOURCE
/sys/src/cmd/pr.c SEE ALSO
cat(1), lp(1) PR(1)
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