Sed/awk join lines once pattern found Post: 302995738

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Top Forums UNIX for Beginners Questions & Answers Sed/awk join lines once pattern found Post 302995738 by krsnadasa on Tuesday 11th of April 2017 01:04:45 PM

04-11-2017

Registered User

Sed/awk join lines once pattern found

Hi all

OS - RHEL6.4

I have input file -f1.txt

Code:

 [=129Dytt.....===..
  
 Sometxt
 \Start\now\fine step
 watch this space for tools 
 ends here 
  
 =--2323UT;;;====.......
  
 \Start\then\go language again
 cubernates space 
 sign in done 
 line again
 do it now

I need to search line which starts with

Code:

\Start

and read next line till it gets blank line and join them all. I need to trim any trailing spaces for each line.So output.txt should be..

Code:

 \Start\now\fine stepwatch this space for toolsends here 
 \Start\then\go language againcubernates spacesign in doneline againdo itnow

I tried ..

Code:

 sed -n '^//Start/{
 s/[ \t]*$// # trim trailing spaces
 N # Move to next line
 s/\n//p #join line and print them

But it goes to next line not beyond. Not sure how to keep lines in buffer till blank line comes.

Tried AWK

Code:

sed -i 's/[ \t]*$//g' f1.txt ; gawk '/^\\Start/{gsub("[\n]","",$0);print $0}RS=""' f1.txt

This gives me only last part

Code:

\Start\then\go language againcubernates spacesign in doneline againdo itnow

Can someone help me out here please?

Thanks

krsnadasa

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