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Top Forums Shell Programming and Scripting Selective printing based on matched record Post 302995540 by dsid on Friday 7th of April 2017 05:28:18 AM
Old 04-07-2017
Quote:
Originally Posted by RavinderSingh13
Hello dsid,

Could you please try following and let me know if this helps.
Code:
awk '/^06[MV].*003529/'  Input_file

NOTE: You had mentioned like after chars M or V, 1 more time M or V should come but couldn't see this into your output, let us know if this is having more conditions etc.

Thanks,
R. Singh

I had tried your command with a little tweak

Code:
awk '/^0[67][MV].*003529/'

and the output I got was what it was supposed to give. However, it isn't exactly suitable for me as I am looking for only those lines which have 003529 in the 26-31 position.

Also there is either a 06M or 06V or 07M or 07V in the line that I need to search. When the regex matches, it should print the next 5 lines, including $0, in total 6 lines.

Hope I am clear now.

---------- Post updated at 10:28 AM ---------- Previous update was at 10:19 AM ----------

Quote:
Originally Posted by RudiC
Try also
Code:
grep -A5 "^0[67][MV].\{22\}003529" file

OR

Code:
awk '/^0[67][MV]......................003529/ {L = NR + 6} NR < L' file

Hi RudiC,

Can you please explain to me what does the part in RED mean?

Also is there a way where we can specify that 003529 comes between position 26,31. Reason Im asking is if there is a need for me to specify characters which are say between the position 100-106 then it kind of becomes difficult for me to mention the dots.

Code:
grep -A5 "^0[67][MV].\{22\}003529" file

is really fast compared to awk
 

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