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Top Forums Shell Programming and Scripting Grep command to search pattern corresponding to input from user Post 302995192 by MadeInGermany on Monday 3rd of April 2017 04:43:32 AM
Old 04-03-2017
I think the o/p wants to search for "scan_out[5]" and get the matching "COS_12_TM_4".
The following searches for [ outside the "string" and on success stores the line, and it searches for ] outside the "string" and on success tries to find the given string and on success prints the stored line.
Code:
awk '{x=$0; sub(/".*"/,"",x)} (index(x,"[")) {sn=$0} (index(x,"]") && index($0,search)) {print sn}' search='scan_out[5]' file

 

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LOOKBIB(1)						      General Commands Manual							LOOKBIB(1)

NAME
lookbib - search bibliographic databases SYNOPSIS
lookbib [ -v ] [ -istring ] [ -tn ] filename... It is possible to have whitespace between a command line option and its parameter. DESCRIPTION
lookbib prints a prompt on the standard error (unless the standard input is not a terminal), reads from the standard input a line contain- ing a set of keywords, searches the bibliographic databases filename... for references containing those keywords, prints any references found on the standard output, and repeats this process until the end of input. For each database filename to be searched, if an index filename.i created by indxbib(1) exists, then it will be searched instead; each index can cover multiple databases. OPTIONS
-v Print the version number. -istring When searching files for which no index exists, ignore the contents of fields whose names are in string. -tn Only require the first n characters of keys to be given. Initially n is 6. FILES
filename.i Index files. SEE ALSO
refer(1), lkbib(1), indxbib(1) Groff Version 1.18.1 27 June 2001 LOOKBIB(1)
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