using sed to replace a specific string on a specific line number using variables
this is where i am at
grep -v WARNING output | grep -v spawn | grep -v Passphrase | grep -v Authentication | grep -v '/sbin/tfadmin netguard -C'| grep -v 'NETWORK>' >> output.clean
grep -n Destination... (2 Replies)
I am trying to use sed to replace specific characters at a specific position in the file with a different value... can this be done?
Example:
File:
A0199999123
A0199999124
A0199999125
Need to replace 99999 in positions 3-7 with 88888.
Any help is appreciated. (5 Replies)
I'm trying to update a text file via sed/awk, after a lot of searching I still can't find a code snippet that I can get to work.
Brief overview:
I have user input a line to a variable, I then find a specific value in this line 10th field in this case. After asking for new input and doing some... (14 Replies)
Hi,
I have a fixed width file.
The way this file works is say for example there are 30 columns in it each with different sizes say 10,5,2, etc...
If data in a field is less than the field size the rest of it is loaded with spaces.
I would like an awk command to that would replace
I have... (8 Replies)
sed -e "s// /g" old.txt > new.txt
While I do know some control characters need to be escaped, can normal characters also be escaped and still work the same way? Basically I do not know all control characters that have a special meaning, for example, ?, ., % have a meaning and have to be escaped... (11 Replies)
Hi experts,
My file looks something like this.
abcXX4,7,234
abc,defg,45XX23,74,123
The number of commas left of the XX can vary. The question is how can I replace all the commas left of the 'XX' with an underscore?
abcXX4,7,234
abc_defg_45XX23,74,123
Thanks! (5 Replies)
Need command for position based replace:
I need a command to replace with 0 for characters in the positions 11 to 20 to all the lines starts with 6 in a file.
For example the file ABC.txt has:
abcdefghijklmnopqrstuvwxyz
6abcdefghijklmnopqrstuvwxyz
abcdefghijklmnopqrstuvwxyz... (4 Replies)
I would like to remove all characters starting with "%" and ending with ")" in the 4th field - please help!!
1412007819.864 /device/services/heartbeatxx 204 0.547%!i(int=0) 0.434 0.112
1412007819.866 /device/services/heartbeatxx 204 0.547%!i(int=1) 0.423 0.123... (10 Replies)
Hi Team,
I have requirement to replace Language Specific Characters in File.
We have set of characters, it should be replaced to a different character in the file.
I have around 38 characters which should replaced to different destination character.
Please help.
Thanks
Bharat (3 Replies)
Discussion started by: bharath561989
3 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)