I have written a script which does a following functions:-
1) Check a area if it is mounted or not
2) If the area is not mounted it will prompt the user to mount the are.
3) Once the area is mounted and the option is given as Y or y
the script continues...
My question is will the below... (2 Replies)
hi,
how can i can pass the value of unixformat to date/time? and how can i retrieve the day/month/year from a date?
thanks a lot for your help
ps:i using php (1 Reply)
I use FreeBSD,and use signal,like follows:
signal(SIGHUP,sig_hup);
signal(SIGIO,sig_io);
when I run call following code,it can run,but I find a puzzled question,it should print some information,such as printf("execute main()") will print execute main(),but in fact,printf fuction print... (2 Replies)
Hello again,
Am having an issue now with getting a simple grep command to work within a function..
The function is as below...
function findRecord() {
output=grep "001" recordDatabase
echo $output
}
At the moment the "001"... (3 Replies)
Hi,
I want to copy a file/directory ( recursively , if needed) and if destination directory does not exist create it ( with parent directory, if needed).
funcopy () {
if ; then
echo "$2 exists , copying files"
cp -r "$1" "$2"
else
echo "Directory does not exist;Create directory"
mkdir... (1 Reply)
Hi All,
I am new to Unix , there i am facing one problem with sleep command. that is ..
in while loop i have defined sleep function ..
my condition is like this
while #i knew this is infinite loop
do
sleep 200
echo "hello "
done.
this condition will never become .. true... (3 Replies)
Hello, and here's my problem:
I can't get my function to do what I want. When I call my function get_from_A_to_F I give it an argument $remainder. I want my function to substitute a number higher than 9 to a specific letter. If the argument is equal to 10 than it should change it to "A".... (8 Replies)
Hi,
I have a process which can run one instance at a time. Currently we have multiple scripts trying to kickoff this process. I wanted to implement the semaphore mechanism to achieve this.
I was going through few examples. The below code seems to be reasonable solution.
... (5 Replies)
Hello everyone
I really hope you can help me, I can't continue:
Im on a project to work with my Server.
I wanted to put on my server all data-systems and I did this:
df -h
The output is a string.
How can I turn the string into a table?
Dateisystem Größe Benutzt Verf. Verw% Eingehängt auf... (5 Replies)
Hi guys and gals...
I am writing a piece of code that is dash compliant and came across this error.
I have put it in the OSX section as that is what I am using.
I have no idea what the 'dash' version is but was installed about 6 months ago.
MBP, OSX 10.12.6, default terminal running dash on... (4 Replies)
Discussion started by: wisecracker
4 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)