I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd'
am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file
As of now am using multiple command to do this, is there a way to do this in single command?
Required output:
I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
I have a file with some date columns in MM/DD/YYYY format:
SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458|
And I want to convert the date format to:
... (5 Replies)
Frens,
I have a logfile which has got manier things in it and somewer in that file i have a date in mm/dd/yyyy hh:mm format....
I just need to get the date and time nothing else....
i have searched in this forum for it but got only date in mm-dd-yyyy format..
but i need to search for... (10 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
could you please help be on the below code ..
Requirement is when i pass the parameter(for below 2) i should get current time -2 hours in the format :wall:..
cur_dt=`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID -P $PASSWD -h -C"select getdate()" | sed '2d'`
pr_dt="`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID... (2 Replies)
Hi,
I am having one log files. contains som data according to date. And it is going to append .Eg:abc.log contains below data
2011-10-19 abjhgj
2011-10-19 gjhgjgj
2011-10-20 hhhjh
2011-10-20 hhhhjj
2011-10-21 gg
.
.
.
2011-11-24 yyy
from log files i want catch only... (2 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am changing epoch times to dates. I was able to do the following:
echo "$varx" | gawk '{print strftime("%c", $0)}'
Mon Dec 31 16:26:40 2012
This changes the epoch date (which is what varx is) into localtime.
However, my problem is that I only want 12/31/2012 and not the Mon Dec 31... (2 Replies)
Discussion started by: newbie2010
2 Replies
LEARN ABOUT CENTOS
grep-changelog
grep-changelog(1) General Commands Manual grep-changelog(1)NAME
grep-changelog - print ChangeLog entries matching criteria
SYNOPSIS
grep-changelog [options] [CHANGELOG...]
DESCRIPTION
grep-changelog searches the named CHANGELOGs (by default files matching the regular expressions ChangeLog and ChangeLog.[0-9]+) for
entries matching the specified criteria. At least one option or file must be specified. This program is distributed with GNU Emacs.
OPTIONS
The program accepts unambiguous abbreviations for option names.
--author=AUTHOR
Print entries whose author matches regular expression AUTHOR.
--text=TEXT
Print entries whose text matches regular expression TEXT.
--exclude=TEXT
Exclude entries matching regular expression TEXT.
--from-date=YYYY-MM-DD
Only consider entries made on or after the given date. ChangeLog date entries not in the "YYYY-MM-DD" format are never matched.
--to-date=YYYY-MM-DD
Only consider entries made on or before the given date.
--rcs-log
Print output in a format suitable for RCS log entries. This format removes author lines, leading spaces, and file names.
--with-date
In RCS log format, print short dates.
--reverse
Show matches in reverse order.
--version
Display version information.
--help Display basic usage information.
COPYING
Copyright (C) 2008-2013 Free Software Foundation, Inc.
Permission is granted to make and distribute verbatim copies of this document provided the copyright notice and this permission notice are
preserved on all copies.
Permission is granted to copy and distribute modified versions of this document under the conditions for verbatim copying, provided that
the entire resulting derived work is distributed under the terms of a permission notice identical to this one.
Permission is granted to copy and distribute translations of this document into another language, under the above conditions for modified
versions, except that this permission notice may be stated in a translation approved by the Free Software Foundation.
grep-changelog(1)