Search for a pattern and replace a space at specific position with a Character in File
In file, we have millions of records each of 1000 in length. And at specific position say 800 there is a space, we need to replace it with Character X if the ID in that row starts with 123.
So far i have used the below which is replacing space at that position to X but its not checking for records which have ID as 123.
Thanks
Moderator's Comments:
Use code tags, thanks.
Last edited by zaxxon; 02-23-2017 at 03:31 AM..
Reason: code tags and indention
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Hi,
I need to add Pipe (|) at 5th and 18th position of all records a file. How can I do this?
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I am trying to use sed to replace specific characters at a specific position in the file with a different value... can this be done?
Example:
File:
A0199999123
A0199999124
A0199999125
Need to replace 99999 in positions 3-7 with 88888.
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How to replace the position specific values in the file..
i searched a lot the forums but i couldn't able to do...
i have file like below
576666666666666666666666666 7878 897987 121 0asdas Y12
5900fbb 777 09JJJ 78798347892374 234234234364 234232898
89HJHIHIGIUG989902743748327khjkhkjlh... (6 Replies)
Hi,
i want find the character '-' in a file from position 284-298, if it occurs i need to replace it with 'O ' for the position in the file. How to do that using SED command.
thanks in advance,
Sara (9 Replies)
Hi,
I have a file with multiple lines(fixed width dat file). I want to search for '02' in the positions 45-46 and if available, in that lines, I need to replace value in position 359 with blank. As I am new to unix, I am not able to figure out how to do this. Can you please help me to achieve... (9 Replies)
I will appreciate if you help me here in this script in Solaris Enviroment.
Scenario:
i have 2 files :
1) /tmp/TRANSACTIONS_DAILY_20180730.txt:
201807300000000004
201807300000000005
201807300000000006
201807300000000007
201807300000000008
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Discussion started by: teokon90
10 Replies
LEARN ABOUT DEBIAN
regexp
Regexp(3I) InterViews Reference Manual Regexp(3I)NAME
Regexp - regular expression searching
SYNOPSIS
#include <InterViews/regexp.h>
DESCRIPTION
A Regexp encapsulates a regular expression pattern and defines operations for searching and matching the pattern against a string. The
syntax of the regular expression pattern is the same as that for ed(1). Information can be obtained about the most recent match of the
regular expression (and its sub-expressions).
PUBLIC OPERATIONS
Regexp(const char* pattern)
Regexp(const char* pattern, int length)
Construct a new Regexp for pattern.
int Match(const char* text, int length, int index)
Attempt a match against text (of length length) at position index. The return value is the length of the matching string, or a neg-
ative number if the match failed.
int Search(const char* text, int length, int index, int range)
Search for a match in the string text (of length length). Matches are attempted starting at positions between index and index plus
range. If range is positive the first match after index is reported. If range is negative the first match before index is
reported. The return value is the index of the starting position of the match, or a negative number if there is no match in the
specified range.
int BeginningOfMatch(int subexp)
int EndOfMatch(int subexp)
Return information about the most recent match. If subexp is zero (the default), information is reported for the complete regular
expression. Other values of subexp refer to sub-expressions in the pattern. For example, if subexp is 2, information is returned
for the sub-expression specified by the second pair of ( and ) delimiters in the pattern.
SEE ALSO ed(1)InterViews 23 May 1989 Regexp(3I)