(Edit: I'd initially typo'd the "2 days" as "2 months" in the output routine. Fixed now, sorry.)
I think I have a solution for you. The script is:
You'll notice that above the 'eval' lines (a command I'm using to do the arithmetic here) there are also commented-out lines using Bash's own built-in 'let' command, which can also do arithmetic. If you don't have 'expr' on your system, then you can comment out or remove the 'expr' lines and go with the 'let' lines instead. I've tested it with both, and (for this one single test input file, it must be noted) all was well.
Here is a transcript of a sample session, using the exact test date string you provided as the input in 'date.txt'.
Hi I am very new to scripting,
Can someone show me how to (in unix shell script) compare the system's date with a date in a file. The requirement is to somehow open this file (which will only have a date in it) and compare it with today's date. If they are equal execute a procedure below but if... (4 Replies)
Hello everyone, I'm in desperate need of your help for this challenge I have below:
The run_dt_tbl has only 1 column and 1 row that contains a particular date in format mmddyy. I want to some how compare today's date with the date in this table that will be preset by someone else. If the dates... (2 Replies)
HI,
I have some files in my Linux machine that are very old and occupy a HUGe amount of space. I am trying to delete these files from the system so that it will be easy for me to add some files. I would like to know if this can done through a Perl or a shell script.
What i want to do is i... (6 Replies)
I am currently running the following Korn shell script which works fine:
#!/usr/bin/ksh
count=`db2 -x "select count(*) from schema.tablename"`
echo "count"
I would like to add a "where" clause to the 2nd line that would allow me to get a record count of all the records from schema.tablename... (9 Replies)
Hello gurus,
I am hoping someone can help me with the required code/script to make this work. I have the following file with records starting at line 4:
NETW~US60~000000000013220694~002~~IT~USD~2.24~20110201~99991231~01~01~20101104~... (4 Replies)
In KSH, I am pasting 2 almost identical files together and each one has a date and time on each line. I need to determine if the first instance of the date/time is greater than the 2nd instance of the date/time. If the first instance is greater, I just need to echo that line.
I thought I would... (4 Replies)
Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if ; then
...proceed commands
... (1 Reply)
Can someone help me with the code wherein there is a file f1.txt with different column and 34 column have expiry date and I need to get that and compare with system date and if expiry date is <system date remove those rows and other rows should be moved to new file f2.txt .
I don't want to delete... (2 Replies)
I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
We want to call a parameter file (.txt) where my application read dynamic values when the job is triggered, one of such values are below:
abc.txt
------------------
Code:
line1
line2
line3
$$EDWS_DATE_INSERT=08-27-2019
line4
$$EDWS_PREV_DATE_INSERT=08-26-2019
I am trying to write a... (3 Replies)
Discussion started by: pradeepp
3 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)