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Top Forums Shell Programming and Scripting Compare the system date with date from a text file Post 302992004 by Loc on Monday 20th of February 2017 01:48:04 PM
Old 02-20-2017
Compare the system date with date from a text file

I get the date that's inside a text file and assigned it to a variable. When I grep the date from the file, I get this,
Code:
Not After : Jul 28 14:09:57 2017 GMT

So I only crop out the date, with this command
Code:
echo $dateFile | cut -d ':' -f 2,4

The result would be
Code:
Jul 28 14:57 2017 GMT

How do I convert this date to the number of seconds, so I can compare it to the system date? If it is over 2 days old.
I have this code but it doesn't work. I'm getting an error message when I ran it. I think its because $dateFile is a text file and it doesn't know how to convert it.
Any help would be appreciated.


Code:
 
 #!/bin/bash
 $dateFile=grep "After :" myfile.txt | cut -d ':' -f 2,4
 AGE_OF_MONTH="172800" # 172800 seconds  = 2 Days
NOW=$( date +%s )
NEW_DATE=$(( NOW - AGE_OF_MONTH ))
 if [ $( stat -c %Y "$dateFile" ) -gt ${NEW_DATE} ]; then
   echo Date Less then 2 days
else
   echo Date Greater then 2 days
fi


Last edited by rbatte1; 02-21-2017 at 08:31 AM.. Reason: Changed bold text to CODE for file contents
 

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DATETIME.ADD(3) 							 1							   DATETIME.ADD(3)

DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::add (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_add (DateTime $object, DateInterval $interval) Adds the specified DateInterval object to the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.add(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); $date->add(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-01'); date_add($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-11 Example #2 Further DateTime.add(3) examples <?php $date = new DateTime('2000-01-01'); $date->add(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-01'); $date->add(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-01 10:00:30 2007-06-05 04:03:02 Example #3 Beware when adding months <?php $date = new DateTime('2000-12-31'); $interval = new DateInterval('P1M'); $date->add($interval); echo $date->format('Y-m-d') . " "; $date->add($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-01-31 2001-03-03 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.sub(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.ADD(3)
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