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Top Forums Shell Programming and Scripting Delete all log files older than 10 day and whose first string of the first line is "MSH" or "<?xml" Post 302991890 by Hiroshi on Friday 17th of February 2017 01:06:53 PM
Old 02-17-2017
Quote:
Originally Posted by RudiC
Just guessing that you are not running a (recent) bash for your "substring expansion" ${firstLine:0:3} as it is the usual syntax and should work. ${cut -c1-8} should be a "command substitution" in the syntax $(cut -c1-8) but needs an input file to work upon.
Come on folks, I need to wake up and so should you. The only problem was that I forget to start with #!/bin/bash, it's all. As soon as I added that, it worked like a charm.

Thank you @RudiC for replying. Your verification of the code gave me enough confidence to go and look elsewhere and find it. Thank you very much.

And thank you all for reading, thinking about replying, etc.

YOU ALL HAVE A VERY NICE WEEKEND (especially you @RudiC). YOU GUYS ARE TRULY AWESOME.
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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