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UNIX for Beginners Questions & Answers
Weird 'find' results
Post 302991866 by durden_tyler on Friday 17th of February 2017 03:36:16 AM
02-17-2017
Quote:
After running your commands on similarly sized files, here's my guess about what is happening.
When you say "-size nS", where "n" is an integer specifying "units of space" and "S" is the suffix (M, k etc.), then the find command searches for files that have a rounded up size of "nS".
That effectively means that the size of the file is > (n-1)S and <= nS.
So, as per this theory, "-size 1M" means files with "rounded up size of 1M", or sizes > 0M and <= 1M. 0M bytes = 0 bytes. Hence files with sizes 183, 2112 etc are displayed.
Code:
$ find . -type f -size 1M -ls 6029496 1000 -rw-r--r-- 1 r2d2 r2d2 1024000 Feb 17 02:32 ./large1.log 6029492 4 -rw-r--r-- 1 r2d2 r2d2 183 Feb 17 02:29 ./graphical.txt 6029493 4 -rw-r--r-- 1 r2d2 r2d2 2112 Feb 17 02:29 ./strace.out 6029494 8 -rw-r--r-- 1 r2d2 r2d2 4659 Feb 17 02:29 ./vmstat.out 6029495 8 -rw-r--r-- 1 r2d2 r2d2 4660 Feb 17 02:30 ./vmstat1.out $
Code:
$ find . -type f -size 2M -ls $
Code:
$ find . -type f -size 3M -ls $
That displays your one file.
Code:
$ find . -type f -size 1000k -ls 6029496 1000 -rw-r--r-- 1 r2d2 r2d2 1024000 Feb 17 02:32 ./large1.log $
Code:
(1) 999k bytes - 1 byte = 1022975 bytes (2) 999k bytes = 1022976 bytes (3) 999k bytes + 1 byte = 1022977 bytes
Code:
perl -e 'foreach (1..1022){foreach (1..999){print chr(97+int(rand(26)))}; print "\n"}' >large1_v1.log
perl -e 'foreach (1..1) {foreach (1..974){print chr(97+int(rand(26)))}; print "\n"}' >>large1_v1.log
perl -e 'foreach (1..1022){foreach (1..999){print chr(97+int(rand(26)))}; print "\n"}' >large1_v2.log
perl -e 'foreach (1..1) {foreach (1..975){print chr(97+int(rand(26)))}; print "\n"}' >>large1_v2.log
perl -e 'foreach (1..1022){foreach (1..999){print chr(97+int(rand(26)))}; print "\n"}' >large1_v3.log
perl -e 'foreach (1..1) {foreach (1..976){print chr(97+int(rand(26)))}; print "\n"}' >>large1_v3.logCode:
$ ls -l total 4024 -rw-r--r-- 1 r2d2 r2d2 183 Feb 17 02:29 graphical.txt -rw-r--r-- 1 r2d2 r2d2 1024000 Feb 17 02:32 large1.log -rw-r--r-- 1 r2d2 r2d2 1022975 Feb 17 02:55 large1_v1.log -rw-r--r-- 1 r2d2 r2d2 1022976 Feb 17 02:55 large1_v2.log -rw-r--r-- 1 r2d2 r2d2 1022977 Feb 17 02:56 large1_v3.log -rw-r--r-- 1 r2d2 r2d2 2112 Feb 17 02:29 strace.out -rw-r--r-- 1 r2d2 r2d2 4660 Feb 17 02:30 vmstat1.out -rw-r--r-- 1 r2d2 r2d2 4659 Feb 17 02:29 vmstat.out $
Code:
$ find . -type f -size 1000k -ls 6029496 1000 -rw-r--r-- 1 r2d2 r2d2 1024000 Feb 17 02:32 ./large1.log 6029500 1000 -rw-r--r-- 1 r2d2 r2d2 1022977 Feb 17 02:56 ./large1_v3.log $
Code:
$ find . -type f -size 999k -ls 6029497 1000 -rw-r--r-- 1 r2d2 r2d2 1022975 Feb 17 02:55 ./large1_v1.log 6029498 1000 -rw-r--r-- 1 r2d2 r2d2 1022976 Feb 17 02:55 ./large1_v2.log $
More tests follow:
Code:
$ $ # size 1k = sizes in the range (0k, 1k] or (0, 1024] $ find . -type f -size 1k -ls 6029492 4 -rw-r--r-- 1 r2d2 r2d2 183 Feb 17 02:29 ./graphical.txt $ $ # size 2k = sizes in the range (1k, 2k] or (1024, 2048] $ find . -type f -size 2k -ls $ $ # size 3k = sizes in the range (2k, 3k] or (2048, 3072] $ find . -type f -size 3k -ls 6029493 4 -rw-r--r-- 1 r2d2 r2d2 2112 Feb 17 02:29 ./strace.out $ $ # size 4k = sizes in the range (3k, 4k] or (3072, 4096] $ find . -type f -size 4k -ls $ $ # size 5k = sizes in the range (4k, 5k] or (4096, 5120] $ find . -type f -size 5k -ls 6029494 8 -rw-r--r-- 1 r2d2 r2d2 4659 Feb 17 02:29 ./vmstat.out 6029495 8 -rw-r--r-- 1 r2d2 r2d2 4660 Feb 17 02:30 ./vmstat1.out $ $
(a) 10.3 blocks i.e. 10 blocks + a fraction of the next block, then its size is considered to be 11 blocks
(b) 4k blocks + a fraction of the next 1k block, then its size is considered to be 5k blocks
(c) 2M blocks + a fraction of the next 1M block, then its size is considered to be 3M blocks
Last edited by durden_tyler; 02-17-2017 at 05:09 AM..
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