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Full Discussion: Dynamic variable name in bash
Top Forums Shell Programming and Scripting Dynamic variable name in bash Post 302991524 by Chubler_XL on Sunday 12th of February 2017 08:09:55 PM
Old 02-12-2017
Quote:
Originally Posted by alex2005
I imagine the problem with this script is when assigning the dynamic variables
Code:
"$var2Value01=$(command 01)"

and
Code:
"$var2Value02=$(command 02)"

Does anyone had similar issues, and if yes how can this be solved?
Using bash you can try:

Code:
declare ${var2}Value01=$(command 01)
declare ${var2}Value02=$(command 02)

or

Code:
printf -v ${var2}Value01 "%s" $(command 01)
printf -v ${var2}Value02 "%s" $(command 02)


These variables can then be referenced using bash indirect expansion like this:

Code:
varname1=${var2}Value01

if [ ! -z ${!varname1} ] ; then
     echo ${!varname1} > file-${!varname1}.err
else
     echo "No errors in $varname1"
fi

Last edited by Chubler_XL; 02-12-2017 at 09:50 PM..
These 2 Users Gave Thanks to Chubler_XL For This Post:
alex2005 wisecracker
 

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