Given that there is no way to know what files might be present in the directory in which this script might be run, to guarantee that you won't get a syntax error in find if .direct* or .xsession* expand to more than one filename, and to guarantee that all files with the desired names will be matched if either of those patterns match a single filename in the current directory, I think it would be safer to change:
in the code Chubler_XL suggested in post #4 to:
(quoting those two filename matching patterns).
It still seems to match files in the current directory when expanding ${F2[*]}, only thing that I could find to avoid it was set -f:
Last edited by Chubler_XL; 02-10-2017 at 08:39 AM..
Hello -
I have a bash script which does some logging, and I'd like to include the line number of the echo statement that pipes into $LOGGER:
MYPID=$$
MYNAME=`basename $0`
LOGGER="/usr/bin/logger -t $MYNAME($LINENO) -p daemon.error"
...
echo 'this is an entry into the log file' | $LOGGER
... (3 Replies)
I have a script that takes an option for server pools to run the script against. The option is given as a comma separated list (ie, -p 201,204,301).
I'm using eval and brace expansion to get those pool numbers into an array. It works fine unless only 1 pool number is given. Here's the code:
... (5 Replies)
i write a batch file , here is the content.
dirname='date +%Y-%m-%d'
mkdir dirname
but it doen's work, it just create a folder named date and +%Y-%m-%d.
i have tried run the command seperately in the bash prompt. after the first
sentence executed , i use $dirname to watch the value of... (4 Replies)
Hello,
is there a kind soul who can answer me, does the SH support double substitution known as indirect expansion similar to BASH? The syntax for bash is ${!var}.
For instance in bash I can write something like this:
VAR="value"
REF_VAR="VAR"
echo ${!REF_VAR}
and get the "value"... (1 Reply)
This is what I have in my directory.
$ ls
test1.txt test2.txt test3.txt test4.txt test5.txt test_script.sh
This is what my shellscript looks like.
#!/bin/bash
for filename in /shell_expansion/*.txt; do
for ((i=0; i<=3; i++)); do
echo "$filename"
... (5 Replies)
I have made the following examples that print various parameter expansions
text: iv-hhz-sac/hpac/hhz.d/iv.hpac..hhz.d.2016.250.070018.sac
(text%.*): iv-hhz-sac/hpac/hhz.d/iv.hpac..hhz.d.2016.250.070018
(text%%.*): iv-hhz-sac/hpac/hhz
(text#*.): d/iv.hpac..hhz.d.2016.250.070018.sac... (2 Replies)
#!/bin/bash
SNMPW='/usr/bin/snmpwalk'
while read h i
do
loc=$($SNMPW -v3 -u 'Myusername' -l authPriv -a SHA -A 'Password1' -x AES -X 'Password2' $i sysLocation.0 2>/dev/null)
loc=${loc:-" is not snmpable."}
loc=${loc##*: }
loc=${loc//,/}
echo "$i,$h,$loc"
done < $1
My question is ... ... (1 Reply)
I am trying to become more fluent with the interworking of bash and minimize the number of external calls.
Sample Data. This will be the response of the snmp query.
SNMPv2-MIB::sysName.0 = STRING: SomeHostName
SNMPv2-MIB::sysObjectID.0 = OID: SNMPv2-SMI::enterprises.9.1.1745... (5 Replies)
Hello All,
Could you please do help me here as I would like to perform parameter expansion in shell over a parameter expansion.
Let's say I have following variable.
path="/var/talend/nat/cdc"
Now to get only nat I could do following.
path1="${path%/*}"
path1="${path1##*/}"
Here... (8 Replies)