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Full Discussion: Bash expansion
Top Forums Shell Programming and Scripting Bash expansion Post 302991326 by jcdole on Thursday 9th of February 2017 06:52:24 AM
Old 02-09-2017
Bash expansion
Hello.
I cannot write a command without using eval.
Any help is welcome

Note 1 : What does the function SOMETHING has no importance.
Note 2 : What does the command find has no importance.

It is an expansion variable problem : where to put ["] or [\"] or [ '] or anythings else

What works (FILTRE_1 and FILTRE_2 are taken into account) :

Code:
function CHERCHE () {

    MY_PATH1="$1"
    if [[  ! -d "$MY_PATH1" ]] ; then
        echo "doing : $MY_PATH1"
        /usr/bin/kate "$MY_PATH1"
    fi
}
export -f CHERCHE

MY_PATH="/home/bidon"

FILTRE_1=" -path  $MY_PATH/.local/share/kscreen  -o -path  $MY_PATH/.local/share/baloo   -o -path  $MY_PATH/.dbus"

FILTRE_2=" ! -name \".direct*\"  ! -name \".Xauthority\"  ! -name \".xsession*\"  ! -name \".bash_history\" "

CMD="find \"$MY_PATH\"  -type d \( $FILTRE_1  \) -prune -o  \( $FILTRE_2 -exec bash -c 'CHERCHE \$0 '  {} \; \)  "
echo "COMMAND : $CMD"
eval "$CMD"

# The command return 9 files which is the good result

What does not works (FILTRE_1 is taken into account, FILTRE_2 or FILTRE_3 or FILTRE_2 is ignored ) :
Filter_2 is same as above

Code:
FILTRE_2=" ! -name \".direct*\"  ! -name \".Xauthority\"  ! -name \".xsession*\"  ! -name \".bash_history\" "

FILTRE_3=' ! -name ".direct*"  ! -name ".Xauthority"  ! -name ".xsession*"  ! -name ".bash_history" '

FILTRE_4=" ! -name '.direct*'  ! -name '.Xauthority' ! -name '.xsession*'  ! -name '.bash_history' "

find "$MY_PATH"  -type d \( $FILTRE_1  \) -prune -o  \( $FILTRE_2 -exec bash -c 'CHERCHE "$0" ' {} \;  \)
#FILTER_2 does nothing

find "$MY_PATH"  -type d \( $FILTRE_1  \) -prune -o  \( $FILTRE_3 -exec bash -c 'CHERCHE "$0" ' {} \;  \)
#FILTER_3 does nothing

find "$MY_PATH"  -type d \( $FILTRE_1  \) -prune -o  \( $FILTRE_4 -exec bash -c 'CHERCHE "$0" ' {} \;  \)
#FILTER_4 does nothing

#Each command return 15 files because filter 3,4,5 , does nothing.

 

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LEARN ABOUT DEBIAN

bashbug

BASHBUG(1)							      bashbug								BASHBUG(1)

NAME

       bashbug - report a bug in bash

SYNOPSIS

       bashbug [--help] [--version] [bug-report-email-addresses]

DESCRIPTION

       bashbug is a utility for reporting bugs in Bash to the maintainers.

       bashbug will start up your preferred editor with a preformatted bug report template for you to fill in. Save the file and quit the editor
       once you have completed the missing fields.  bashbug will notify you of any problems with the report and ask for confirmation before
       sending it. By default the bug report is mailed to both the GNU developers and the Debian Bash maintainers. The recipients can be changed
       by giving a comma separated list of bug-report-email-addresses.

       If you invoke bashbug by accident, just quit your editor. You will always be asked for confirmation before a bug report is sent.

OPTIONS

       --help
	      Show a brief usage message and exit.

       --version
	      Show the version of bashbug and exit.

       bug-report-email-addresses
	      Comma separated list of recipients' email addresses. By default the report is mailed to both the GNU developers and the Debian Bash
	      maintainers.

ENVIRONMENT

       DEFEDITOR
	      Editor to use for editing the bug report.

       EDITOR
	      Editor to use for editing the bug report (overridden by DEFEDITOR).

SEE ALSO

       bash(1), reportbug(1), update-alternatives(8) for preferred editor.

AUTHOR

       This manual page was written by Christer Andersson <klamm@comhem.se> for the Debian project (but may be used by others).

GNU Bash 3.1							 11 December 2007							BASHBUG(1)
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