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Top Forums Shell Programming and Scripting Returning an exit code from a bash function Post 302989943 by Don Cragun on Friday 20th of January 2017 01:30:41 AM
Old 01-20-2017
The bash shell script:
Code:
#!/bin/bash

return main

does not make any attempt to run the utility named main. And, as jim mcnamara already said, you don't use return to exit from a bash shell script. According to the standards, using return when you are not inside a function or inside a script invoked by the . command produces unspecified results. Running that script with bash prints two diagnostic messages:
Code:
load.sh: line 2: return: main: numeric argument required
load.sh: line 2: return: can only `return' from a function or sourced script

and exits with exit code 1. Running that same script with ksh produces no diagnostics and exits with exit code 0.

If you just want a shell script that invokes a utility named main and exits with an exit code matching that returned by main, you can use any of the following:
Code:
#!/bin/bash
main
rc=$?
if [ $rc -eq 0 ]
then	exit 0
else	exit $rc
fi

or:
Code:
#!/bin/bash
main
rc=$?
if [ $rc -eq 0 ]
then	exit 0
fi
exit $rc

or:
Code:
#!/bin/bash
main
rc=$?
exit $rc

or:
Code:
#!/bin/bash
main
exit $?

or, more simply, just:
Code:
#!/bin/bash
main

This User Gave Thanks to Don Cragun For This Post:
 

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