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Full Discussion: Shell Variable visibility
Top Forums Shell Programming and Scripting Shell Variable visibility Post 302989536 by Don Cragun on Friday 13th of January 2017 11:37:27 PM
Old 01-14-2017
Quote:
Originally Posted by dae
Many thanks to all of you for your answers ...

Few comments I would like to add:

1. Peasant, I do not think a subshell is created when using that syntax: in fact, I show the PID for both functions and I do not notice a specific PID for "while loop" with the first function:

fnct_dae_V1:


Code:
[x004191a@xsnl11p317a log]$ fnct_dae_V1 ()
> {
>
>   echo "PID_Fonction: $$"
>
>   var=0
>
>   cat "STG_INSTNCE_COMPLTED_01_451_20170112193018.log" | while read -r line
>   do
>
>     if [[ $(echo "$line" | grep -i 'completed') ]]
>     then
>
>       ((var++))
>
>     echo "- INSIDE WHILE:var:$var"
>     echo "PID_WHILE: $$"
>
>     fi
>
>   done
>
>   echo "- OUTSIDE WHILE:var:$var"
>
> }
[x004191a@xsnl11p317a log]$ fnct_dae_V1
PID_Fonction: 15468
- INSIDE WHILE:var:1
PID_WHILE: 15468
- INSIDE WHILE:var:2
PID_WHILE: 15468
- INSIDE WHILE:var:3
PID_WHILE: 15468
- INSIDE WHILE:var:4
PID_WHILE: 15468
- OUTSIDE WHILE:var:0
[x004191a@xsnl11p317a log]$


fnct_dae_V2:


Code:
[x004191a@xsnl11p317a log]$ fnct_dae_V2 ()
> {
>
>   echo "PID_Fonction: $$"
>
>   var=0
>
>   while read -r line
>
>   do
>
>     if [[ $(echo "$line" | grep -i 'completed') ]]
>     then
>
>       ((var++))
>
>     echo "- INSIDE WHILE:var:$var"
>     echo "PID_WHILE: $$"
>
>     fi
>
>   done < STG_INSTNCE_COMPLTED_01_451_20170112193018.log
>
>   echo "- OUTSIDE WHILE:var:$var"
>
> }
[x004191a@xsnl11p317a log]$ fnct_dae_V2
PID_Fonction: 15468
- INSIDE WHILE:var:1
PID_WHILE: 15468
- INSIDE WHILE:var:2
PID_WHILE: 15468
- INSIDE WHILE:var:3
PID_WHILE: 15468
- INSIDE WHILE:var:4
PID_WHILE: 15468
- OUTSIDE WHILE:var:4
[x004191a@xsnl11p317a log]$

2. Scrutinizer, I applied your suggestion (illustration below with fnct_dae_V3) but, in that case, it seems that I can not keep the value of the variable with that syntax:

fnct_dae_V3:


Code:
[x004191a@xsnl11p317a log]$ fnct_dae_V3 ()
> {
>
>   echo "PID_Fonction: $$"
>
>   var=0
>
>   cat "STG_INSTNCE_COMPLTED_01_451_20170112193018.log" |
>
>   {
>
>     while read -r line
>     do
>
>       if [[ $(echo "$line" | grep -i 'completed') ]]
>       then
>
>         ((var++))
>
>       echo "- INSIDE WHILE:var:$var"
>       echo "PID_WHILE: $$"
>
>       fi
>
>     done
>
>   }
>
>   echo "- OUTSIDE WHILE:var:$var"
>
> }
[x004191a@xsnl11p317a log]$ fnct_dae_V3
PID_Fonction: 15468
- INSIDE WHILE:var:1
PID_WHILE: 15468
- INSIDE WHILE:var:2
PID_WHILE: 15468
- INSIDE WHILE:var:3
PID_WHILE: 15468
- INSIDE WHILE:var:4
PID_WHILE: 15468
- OUTSIDE WHILE:var:0
[x004191a@xsnl11p317a log]$

So, I allow myself to ask you one more time: how is it possible to lose the value of the variable if the whole execution use a unique PID (cf. fnct_dae_V1 and I assume fnct_dae_V3) ?

Thanks again, Smilie
You did not apply Scrutinizer's suggestion. And, a subshell and a separate process are two distinct things. And, again, the response is exactly the same. Using cat and a pipeline to feed input into your while read loop places the while read loop in a subshell (when you are using bash and many other shells). Get rid of the unneeded cat (which creates an extra process, drains system resources, and slows down your script without serving any useful purpose) and the subshell, and it will work just fine. Or, if you use a Korn shell (ksh) instead of the shell you're currently using, the last stage of a pipeline will be run in the current shell execution environment instead of in a subshell environment. (But, I haven't checked to see if you are using any other extensions to the POSIX standard shell requirements that might be treated differently by ksh than they are in the shell you're currently using.)
This User Gave Thanks to Don Cragun For This Post:
 

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