12-29-2016
How to compare previous and current item in for loop in bash?
Hey,
I am trying to compare formated login and logout dates from one user at a host which I have stored in a tmp directory in order to find out the total login time. I need to compare them in order to find overlapping intervals.
At first I tried to store each log in and logo date in an array but it doesn't work. Can anyone help me?
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
How do you get a for loop to cope with one of the items being an asterisk?
for myResult in `echo "*"`
do
echo "$myResult"
done
The asterisk is returning a file listing in the PWD.
The same result can be got from:
for myResult in "*"
do
echo "$myResult"
done (1 Reply)
Discussion started by: PaulUrwin
1 Replies
2. Shell Programming and Scripting
hi,
i am new to this site.
i want to write a script to compare the file size of the files in the current dir with the files in the previous directory.
the files name will be same, but the filename format will be as xyzddddyymm.txt. the files will arrive with the month end date(i want to... (5 Replies)
Discussion started by: tweety
5 Replies
3. Shell Programming and Scripting
Hi,
I have one small doubt how to go ahead and process the below requirement.
File Content
1,abc,10
2,xyz,11
3,pqr,12
4,pqr,13
5,pqr,14
Output file expected:
1,mnq,1
1,ddd,2
1,qqq,3
1,sss,4
1,ddd,5
1,eee,6
1,fff,7
1,ddr,8
1,rrd,9 (3 Replies)
Discussion started by: dikesm
3 Replies
4. Shell Programming and Scripting
Hi Guys
I have the following file
Essentially, I am trying to find the right awk/sed syntax in order to produce the following 3 distinct files from the file above:
Basically, I want to print the lines of the file as long as the second field of the current line is equal to the... (9 Replies)
Discussion started by: moutaye
9 Replies
5. Shell Programming and Scripting
Hi! all
can any one tell me how to compare current record of column with next and previous record in awk without using array
my case is like this
input.txt
0 32
1 26
2 27
3 34
4 26
5 25
6 24
9 23
0 32
1 28
2 15
3 26
4 24 (7 Replies)
Discussion started by: Dona Clara
7 Replies
6. Shell Programming and Scripting
For example, I have a file called number.txt.
x y
1 1
2 4
3 9
4 6
5 5
6 6
7 9
8 4
9 1
10 0
...
And I want to print out the value of x and y, if y%4==0 and the next value of y%4==0. Thus, the sample output is:
1 1 *because the previous x before 2 is 1
2 4 *because 4%4 == 0
7 9... (2 Replies)
Discussion started by: Tzeronone
2 Replies
7. Shell Programming and Scripting
Hello,
I'm new here. I test these expressions's value in my script :
(in centOS 6 )
#!/bin/bash
array='something'
echo "############"
echo ${array}
echo ${array}
echo ${array}
echo "############"
The output result is :
#################
something
something
#################... (5 Replies)
Discussion started by: lingjing
5 Replies
8. Shell Programming and Scripting
Hi Gurus,
I have requirement to compare current result with previous reuslt.
The sample case is below.
1 job1 1
1 job2 2
1 job3 3
2 job_a1 1
2 job_a2 2
2 job_a3 3
3 job_b1 1
3 job_b2 2
for above sample file, GID is group ID, for input line, the job run... (1 Reply)
Discussion started by: ken6503
1 Replies
9. Shell Programming and Scripting
Hello All,
I'm working on a script that will actually read a file consisting of data like the below:(ReportID,Sub_reportID,Sub_reportName)
1,1,ABC
1,2,DEF
1,3,GHI
2,1,JKL
2,2,MNO
3,1,PQR
I want to read the Sub Report details for a Report_ID using while loop and write these values into... (6 Replies)
Discussion started by: venkat_reddy
6 Replies
10. Shell Programming and Scripting
We have a simple menu with prompt of menu numbers to user.
It is still under construction.
Is there a way to "count" the menu choices so the prompt maximum count can be changed dynamically?
See attached TODO note in code
read_options(){
local choice
# the... (7 Replies)
Discussion started by: annacreek
7 Replies
LEARN ABOUT DEBIAN
pam_lastlog
PAM_LASTLOG(8) Linux-PAM Manual PAM_LASTLOG(8)
NAME
pam_lastlog - PAM module to display date of last login
SYNOPSIS
pam_lastlog.so [debug] [silent] [never] [nodate] [nohost] [noterm] [nowtmp] [noupdate] [showfailed]
DESCRIPTION
pam_lastlog is a PAM module to display a line of information about the last login of the user. In addition, the module maintains the
/var/log/lastlog file.
Some applications may perform this function themselves. In such cases, this module is not necessary.
OPTIONS
debug
Print debug information.
silent
Don't inform the user about any previous login, just update the /var/log/lastlog file.
never
If the /var/log/lastlog file does not contain any old entries for the user, indicate that the user has never previously logged in with
a welcome message.
nodate
Don't display the date of the last login.
noterm
Don't display the terminal name on which the last login was attempted.
nohost
Don't indicate from which host the last login was attempted.
nowtmp
Don't update the wtmp entry.
noupdate
Don't update any file.
showfailed
Display number of failed login attempts and the date of the last failed attempt from btmp. The date is not displayed when nodate is
specified.
MODULE TYPES PROVIDED
Only the session module type is provided.
RETURN VALUES
PAM_SUCCESS
Everything was successful.
PAM_SERVICE_ERR
Internal service module error.
PAM_USER_UNKNOWN
User not known.
EXAMPLES
Add the following line to /etc/pam.d/login to display the last login time of an user:
session required pam_lastlog.so nowtmp
FILES
/var/log/lastlog
Lastlog logging file
SEE ALSO
pam.conf(5), pam.d(5), pam(7)
AUTHOR
pam_lastlog was written by Andrew G. Morgan <morgan@kernel.org>.
Linux-PAM Manual 06/04/2011 PAM_LASTLOG(8)