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Top Forums Shell Programming and Scripting Filesystem pattern match in awk Post 302987608 by sam_bd on Tuesday 13th of December 2016 09:31:19 AM
Old 12-13-2016
Error Filesystem pattern match in awk

Hi, I'm trying to grep appln processes using its filesystem and also using awk to get accurate results, however when i'm uisng the filesystem in awk statement i'm getting error. Requesting help.

Code:
ps -eaf | grep ApplnName | awk '/ /opt/xxx/yyy / { print }'

Trying with this above code; getting error
Code:
syntax error The source line is 1.
 The error context is
                / /opt/xxx/yyy / >>>  { <<<
 awk: Quitting

also tried ps -eaf | grep ApplnName | awk '/ \/opt/xxx/yyy\/ { print }' but getting same error

Last edited by rbatte1; 12-13-2016 at 10:51 AM.. Reason: Changed one pair of ICODE & HTML tags to CODE tags.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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