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Full Discussion: Bash script - Remove the 3 top level of a full path filename
Top Forums UNIX for Beginners Questions & Answers Bash script - Remove the 3 top level of a full path filename Post 302986617 by jcdole on Monday 28th of November 2016 11:03:03 AM
Old 11-28-2016
Quote:
Originally Posted by Peasant
I'm not sure i follow ... but it looks like rsync could do the job for you ?
I have a try.

---------- Post updated at 16:46 ---------- Previous update was at 16:42 ----------

I have done this which works :
Code:
for MY_FILE in $( find "$SRC" -type f \( -iname "*$SEARCH1*" ! -iname "*~" \)  ) ; do
                    A_PATH=$( echo $MY_FILE | cut -d'/' -f6- )
                    DEST_PATH="/$A_PATH"
                    DEST_DIR_NEW=${DEST_PATH%/*}
                    mkdir -p "$DEST_DIR_NEW"
                    cp -fv  "$MY_FILE"  "$DEST_PATH"
done

---------- Post updated at 17:03 ---------- Previous update was at 16:46 ----------

Quote:
Originally Posted by Peasant
I'm not sure i follow ... but it looks like rsync could do the job for you ?
rsync does not create missing directories in destination.
So it is not better than cp
 

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