1. Shell Programming and Scripting

Hello I am executing the following script nawk 'NR == 1 || substr($0,63,5) ~ /H... / && \ _++ == 2 { fn && close(fn); fn = "part_" ++c; _ = 1 } { print > fn }' sample.dat When i execute as it is it is executing fine. but when i execute the whole script as a single line like below ... (2 Replies)

2. Shell Programming and Scripting

My script is as below : #!/bin/sh for line in `cat Results.txt` do FEILD1=`echo $line |awk -F"|" '{print $1}'` FEILD2=`echo $line |awk -F"|" '{print $2}'` FEILD3=`echo $line |awk -F"|" '{print $3}'` FEILD4=`echo $line |awk -F"|" '{print $4}'` echo "$FEILD1 $FIELD2 $FIELD3 $FIELD4" done ... (15 Replies)

3. Shell Programming and Scripting

I am executing the below in telnet #!/usr/bin/ksh File1=simple.txt # The file to check LogFile=simple.log # The log file DelayMax=30 # Timeout delay Tolerance=2 # BEGIN ############################## while true do StampNow=$(date +%s)/60 # stamp in minutes ... (3 Replies)

4. UNIX for Dummies Questions & Answers

Hi , I m getting an error after executing the script. My script. Script is used to find out the date on 8 different machines(mentioned in SERVERNAMES file). I have added public key to avoid ssh password and ssh without password working fine. #!/bin/sh fn_VMFind() { Date=`ssh -t... (5 Replies)

5. UNIX for Dummies Questions & Answers

# cat SERVERNAMES 10.180.8.231 10.180.8.232 10.180.8.233 10.180.8.234 10.180.8.235 10.180.8.236 10.180.8.237 10.180.8.238 10.180.9.239 fn_Exit() { echo "Machine Doesnt exist" exit 1 #exit shell script } (2 Replies)

6. Shell Programming and Scripting

Hi Please assist. Im getting an error while execuing the script name d "cdsnd.basel.cd_new " as siiadm user. Thanks. siiadm> ls -l total 64 -rwxr-xr-x 1 siiadm sboadm 1004 Sep 17 2008 cdsnd.basel.cd -rwxr-xr-x 1 siiadm sapsys 998 Nov 16 09:14 cdsnd.basel.cd_new... (1 Reply)

7. Shell Programming and Scripting

Please delete de thread. Thanks. (10 Replies)

8. Shell Programming and Scripting

Hi, Seen below is a simple date script. #! /bin/ksh VL = `date +%m/%d` VL1 = `TZ=GMT+24 date +%m/%d` VL2 = `TZ=GMT+48 date +%m/%d` VL3 = `TZ=GMT+72 date +%m/%d` VL4 = `TZ=GMT+96 date +%m/%d` VL5 = `TZ=GMT+120 date +%m/%d` echo $VL echo $VL1 echo $VL2 echo $VL3 echo $VL4 echo... (2 Replies)

9. UNIX for Dummies Questions & Answers

I have the following script test.sh owned by dwdev account and group dwdev, the permissions on the script are as follows. -rw-r-x--- 1 dwdev dwdev 279 Sep 17 13:19 test.sh Groups: cat /etc/group | grep dwdev dwdev:x:704:dwdev dwgroup:x:725:dwdev writers:x:726:dwdev User: cat /etc/passwd |... (3 Replies)

10. Red Hat

Hi, I wrote this script to test if the output for DIR1 and DIR2 comes out as I want : #!/bin/bash DAY=$(date +%d) MONTH=$(date +%b) YEAR=$(date +%Y) DIR1=$($MONTH$YEAR"_Blast_BC01") DIR2=$($MONTH$YEAR"_Blast_BC15") echo $DIR1 echo $DIR2 This is the output I want for echo $DIR1 ... (12 Replies)