AWK subtraction in multiple columns
Hi there,
Can not get the following:
input: 34523 934
9485 3847
394 3847
3456 9384
awk 'NR==1 {for (i = 1; i <= NF; i++) {n=$i; next}; {n-=$i} END {print n}' input
output: 21188 first column only,... (2 Replies)
Hi,
I'm trying to reformat a file to create a new columns reflecting the previous 2 over and over. By that I mean currently each observation has two columns and I want to create a third which has a value equal to 1 minus the sum of the previous two.
This is slightly complicated as 1) I... (6 Replies)
I can't seem to get this to work.
I can reformat the date field if it's the first field (and only field) in the file:
However, I get a syntax error when the date field is the second field (or has any other columns following):
I can use a ";" but then it puts each column on separate... (8 Replies)
Hi everyone!!
I need to apply a simple command to extract columns from a matrix, but I need to extract contemporary from the first to the tenth columns, than from the eleventh to the twentyth and so on...
how can i do that? (1 Reply)
Hi All,
I need the modification for the below mentioned code (found in one more post https://www.unix.com/shell-programming-scripting/27161-script-generate-average-values.html) to find the average values for all the columns(but for a specific rows) and print the averages side by side.
I have... (4 Replies)
Hi experts,
I want to group by average, for multiple columns starting column $7 until NF,
group by ($1-$5), please help
For just 7th column, I can do
awk '
NR>1{
arr += $7
count += 1
}
END{
for (a in arr) {
print a, arr/count
... (10 Replies)
I have the following format of input from multiple files
File 1
24.01 -81.01 1.0
24.02 -81.02 5.0
24.03 -81.03 0.0
File 2
24.01 -81.01 2.0
24.02 -81.02 -5.0
24.03 -81.03 10.0
I need to scan through the files and when the first 2 columns match I... (18 Replies)
Hi guys,
I have hundreds file like this, here I only show two of them:
file 1
feco4_s_BB95.log ZE_1=-1717.5206260
feco4_t_BB95.log ZE_1=-1717.5169250
feco5_s_BB95.log ZE_1=-1830.9322060... (11 Replies)
Hello All;
I have two files with below conditions:
1. Entries in file A is missing in file B (primary is field 1)
2. Entries in file B is missing in file A (primary is field 1)
3. Field 1 is present in both files but Field 2 is different.
Example Content:
File A
... (4 Replies)
Discussion started by: mystition
4 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)