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Top Forums Shell Programming and Scripting awk to remove line if field has symbols in it Post 302985891 by Chubler_XL on Wednesday 16th of November 2016 09:16:45 PM
Old 11-16-2016
Another approach is to only print a line if it does not contain ; AND it does not contain :

Code:
awk '$1 !~ /;/ && $1 !~ /:/ { print }' file

This User Gave Thanks to Chubler_XL For This Post:
 

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GRUB-RENDER-LABEL(1)                                               User Commands                                              GRUB-RENDER-LABEL(1)

NAME
grub-render-label - generate a .disk_label for Apple Macs. SYNOPSIS
grub-render-label [OPTION...] [OPTIONS] DESCRIPTION
Render Apple .disk_label. -b, --bgcolor=COLOR use COLOR for background -c, --color=COLOR use COLOR for text -f, --font=FILE use FILE as font (PF2). -i, --input=FILE read text from FILE. -o, --output=FILE set output filename. Default is STDOUT -t, --text=STRING set the label to render -v, --verbose print verbose messages. -?, --help give this help list --usage give a short usage message -V, --version print program version Mandatory or optional arguments to long options are also mandatory or optional for any corresponding short options. REPORTING BUGS
Report bugs to <bug-grub@gnu.org>. SEE ALSO
The full documentation for grub-render-label is maintained as a Texinfo manual. If the info and grub-render-label programs are properly installed at your site, the command info grub-render-label should give you access to the complete manual. grub-render-label (GRUB) 2.02-2ubuntu8.3 July 2018 GRUB-RENDER-LABEL(1)
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