I've got a file (numbers.txt) filled with numbers and I want to replace each one of those numbers with a new random number between 0 and 9. This is my script so far:
#!/bin/bash
rand=$(($RANDOM % 9))
sed -i s//$rand/g numbers.txtThe problem that I have is that it replaces each number with just... (2 Replies)
Input:
Youcaneasilydothisbyhighlightingyourcode.
Putting space after three characters.
You can eas ily dot his byh igh lig hti ngy our cod e.
How can i do this using sed? (10 Replies)
i need to replace the any special characters with escape characters like below.
test!=123-> test\!\=123
!@#$%^&*()-= to be replaced by
\!\@\#\$\%\^\&\*\(\)\-\= (8 Replies)
I created a awk state to calculate the number of success however when the query runs it has a leading zero. Any ideas on how to remove the leading zero from the calculation?
Here is my query:
cat myfile.log | grep | awk '{print $2,$3,$7,$11,$15,$19,$23,$27,$31,$35($19/$15*100)}'
02:00:00... (1 Reply)
Thank you for 4 looking this post.
We have a tab delimited file where we are facing problem in a lot of funny character. I have tried using awk but failed that is not working.
In the 5th field ID which is supposed to be a integer only of that file, we are getting corrupted data as below.
I... (12 Replies)
I would like to remove all characters starting with "%" and ending with ")" in the 4th field - please help!!
1412007819.864 /device/services/heartbeatxx 204 0.547%!i(int=0) 0.434 0.112
1412007819.866 /device/services/heartbeatxx 204 0.547%!i(int=1) 0.423 0.123... (10 Replies)
here's what im trying to do.
i have a file containing lines similar to this:
data.txt:
1hsRmRsbHRiSFZNTTA1dlEyMWFkbU5wUW5CSlIyeDFTVU5SYjJOSFRuWmpia0ZuWXpKV2FHTnRU
1lKUnpWMldrZFZaMG95V25oYQpSelEyWTBka2QyRklhSHBrUjA1b1kwUkJkd3BOVXpWM1lVaG5k... (5 Replies)
Hi Folks -
I need help manipulating a file.
For column 2, I need to replace the first 3 leading zeros with spaces.
The file looks like such:
00098|00011250000003|00000000000.0200|D|1|07|51|04INDP |04|00820|CS|000000|092717|000000000000.0000|000|... (3 Replies)
Discussion started by: SIMMS7400
3 Replies
LEARN ABOUT DEBIAN
paps
PAPS(1) General Commands Manual PAPS(1)NAME
paps - UTF-8 to PostScript converter using Pango
SYNOPSIS
paps [options] files...
DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves
through the pango ft2 backend.
OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is
included below.
--landscape
Landscape output. Default is portrait.
--columns=cl
Number of columns output. Default is 1.
Please notice this option isn't related to the terminal length as in a "80 culums terminal".
--font=desc
Set the font description. Default is Monospace 12.
--rtl Do right to left (RTL) layout.
--paper ps
Choose paper size. Known paper sizes are legal, letter and A4. Default is A4.
Postscript points
Each postscript point equals to 1/72 of an inch. 36 points are 1/2 of an inch.
--bottom-margin=bm
Set bottom margin. Default is 36 postscript points.
--top-margin=tm
Set top margin. Default is 36 postscript points.
--left-margin=lm
Set left margin. Default is 36 postscript points.
--right-margin=rm
Set right margin. Default is 36 postscript points.
--gutter-width=gw
Set gutter width. Default is 40 postscript points.
--help Show summary of options.
--header
Draw page header for each page.
--markup
Interpret the text as pango markup.
--lpi Set the lines per inch. This determines the line spacing.
--cpi Set the characters per inch. This is an alternative method of specifying the font size.
--stretch-chars
Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops
behaviour.
AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>.
This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others).
April 17, 2006 PAPS(1)