Thanks!
Slight modification to the original problem:

So previously I wanted to replace the last digit before the single quote at end of line with a new value, but now I want to only do it based on the previous digits and a matching pattern.

If any(part of) line in file matches a certain pattern, replace the value after the last dot (and keep the single quote at end of line-same as before) with the value in pattern.
Can I do this using sed?


example:
Pattern to match=name1:1.2.300.Y (or could be name1:1.300.Y, so Y can be any number, I don't care what it is at this point).

All lines will be in the same format and ideally there will only be one line containing 'name1'.

Pattern to match= name1:1.2.300.Y

Original file:

Code:

person1_desc: 'info:200/text/name1:1.2.300.X'
person1_desc: 'info:200/text/name1:1.2.400.A'
person1_desc: 'info:200/text/name1:5.6.700.B'
person2_desc: 'info:200/text/name2:1.2.300.C'

Output file:

Code:

person1_desc: 'info:200/text/name1:1.2.300.Y'
person1_desc: 'info:200/text/name1:1.2.400.A'
person1_desc: 'info:200/text/name1:5.6.700.B'
person2_desc: 'info:200/text/name2:1.2.300.C'

So only the first line was a match and updated, 'X' was replaced with 'Y'. Line 4 wasn't changed( name2)



Pattern I'm looking for:

Code:

name1:1.2.300.Y

In other words:
{string}:{ a combination of one or more numbers and dots, not always 2 dots, but grouped together}.{one or more digits}

Or if I could also extract each field above from the original file into variables:

Code:

Var1=name1
Var2=1.2.300
Var3=Y

If it helps, my pattern-to-look-for could also be:

Code:

info:200/text/name1:1.2.300.Y

Instead of just:

Code:

name1:1.2.300.Y

I hope I explained it well, sorry if I might have over done it!
Thanks!!

---------- Post updated at 10:49 PM ---------- Previous update was at 10:48 PM ----------


Yes that works, thank you!
Slight modification to original problem:


previously I wanted to replace the last digit before the single quote at end of line with a new value, but now I want to only do it based on the previous digits and a matching pattern.

If any(part of) line in file matches a certain pattern, replace the value after the last dot (and keep the single quote at end of line-same as before) with the value in pattern.
Can I do this using sed?


example:
Pattern to match= name1:1.2.300.Y (or could be name1:1.300.Y, so Y can be any number, I don't care what it is at this point).

All lines will be in the same format and ideally there will only be one line containing 'name1'.

Pattern to match= name1:1.2.300.Y

Original file:

Code:

person1_desc: 'info:200/text/name1:1.2.300.X'
person1_desc: 'info:200/text/name1:1.2.400.A'
person1_desc: 'info:200/text/name1:5.6.700.B'
person2_desc: 'info:200/text/name2:1.2.300.C'

Output file:

Code:

person1_desc: 'info:200/text/name1:1.2.300.Y'
person1_desc: 'info:200/text/name1:1.2.400.A'
person1_desc: 'info:200/text/name1:5.6.700.B'
person2_desc: 'info:200/text/name2:1.2.300.C'

So only the first line was a match and updated, 'X' was replaced with 'Y'. Line 4 wasn't changed( name2)



Pattern I'm looking for:

Code:

name1:1.2.300.Y

In other words:
{string}:{ a combination of one or more numbers and dots, not always 2 dots, but grouped together}.{one or more digits}

Or if I could also extract each field above from the original file into variables:

Code:

Var1=name1
Var2=1.2.300
Var3=Y

If it helps, my pattern-to-look-for could also be:

Code:

info:200/text/name1:1.2.300.Y

Instead of just:

Code:

name1:1.2.300.Y

I hope I explained it well, sorry if I might have over done it!
Thanks!!

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