Sponsored Content
Top Forums UNIX for Beginners Questions & Answers Results of ldapsearch piped to grep are cut off Post 302983461 by RudiC on Tuesday 11th of October 2016 04:38:46 PM
Old 10-11-2016
Column width of 80?
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

assigning a multiline grep output which has been piped through sed to a shell variabl

Hi, I wish to format the output of a grep command in such a way that sed will be able to handle the newline characters held in the output. Since sed does not allow newlines to be contained in a replacement pattern, that means adding a backslash '\' character to the end of each line from... (8 Replies)
Discussion started by: timculhane
8 Replies

2. UNIX for Dummies Questions & Answers

How to trim ldapsearch results

I have a script that iterates through all the users that have logged in to the system for the past day and pulls out their role(s), adding them to a file. The iteration part is working just fine, but the issue I have is with the result. When I do the LDAP query, the results I get are: ... (2 Replies)
Discussion started by: a_calder
2 Replies

3. UNIX for Advanced & Expert Users

Counting the ldapsearch results

Hi, Is there way to count the number of results in the ldapsearch, looking at the manpages i dont see an option, Using the following ldapsearch command to list attribute (User-Id=100) under my ObjectClass=my-Process, returns the entries matching the User-Id=100, and the problem i face here is... (0 Replies)
Discussion started by: ennstate
0 Replies

4. Slackware

How should I cut this line using cut and grep?

not sure how to do it. wan't to delete it using cut and grep ince i would use it in the shell. but how must the command be? grep "64.233.181.103 wwwGoogle.com" /etc/hosts | cut -d the delimeter is just a space. can you help meplease. :D (1 Reply)
Discussion started by: garfish
1 Replies

5. Shell Programming and Scripting

Grep no results

Hello guys, I have been looking around but can't find the answer to my problem: If the grep command displays no results, print "no results have been found" and increment x. But if the grep command find something, do nothing. if echo "no results have been found $x" x=`expr $x + 1 `... (3 Replies)
Discussion started by: Benou
3 Replies

6. UNIX for Dummies Questions & Answers

Confused over results using "tee" in piped command

First post here, so hopefully all guidelines are followed, and thanks in advance for any replies. I'm working on a shell script(BASH) that processes a csv file and performs various tasks with the data. All is well, except I want to use 'tee' to send output from 'wc' to a file as well as pipe it... (4 Replies)
Discussion started by: jazzmusic
4 Replies

7. UNIX for Advanced & Expert Users

Place the results of a CUT command into a variable

I am being passed a file in UNIX, ie: variable.txt I need to extract the first part of the file content, up to the period, content ie: common_dir.second_output cut -d'.' -f1 /content/stores/variable.txt I then need to utilize the results to create a variable ($1), and test on that... (4 Replies)
Discussion started by: talonbow
4 Replies

8. Shell Programming and Scripting

Cannot get results from grep command

Hi, i have a file hello.log which as several line that look like the below 2015-12-07 09:46:56 0:339 120.111.12.12 POST /helloWorld 2015-12-07 09:46:57 0:439 122.111.12.12 POST /helloWorld .... when i grep expecting to see results like the below. ... (6 Replies)
Discussion started by: mohtashims
6 Replies

9. UNIX for Beginners Questions & Answers

Ldapsearch returning base64 encoded results

So my ldapsearch works great, except for some results I found today. My search is: /usr/lib64/mozldap/ldapsearch -T -h 10.1.1.1 -p 3891 -D "uid=datapower,ou=People,dc=blah,dc=com" -w xxxxxx -b "ou=Certs,dc=blah,dc=com"... (0 Replies)
Discussion started by: primerib
0 Replies

10. Shell Programming and Scripting

Use cut output as variable piped awk command

Hi, I would like use the output of my cut command as a variable in my following awk command. Here's what I've written. cut -f1 info.txt | awk -v i=xargs -F'' '{if($6 == $i) print $20}' summary.txt Where obviously the 'xargs' doesn't do what I want. How can I pass my cut result to my awk... (3 Replies)
Discussion started by: heyooo
3 Replies
CUBRID_NEXT_RESULT(3)							 1						     CUBRID_NEXT_RESULT(3)

cubrid_next_result - Get result of next query when executing multiple SQL statements

SYNOPSIS
bool cubrid_next_result (resource $result) DESCRIPTION
The cubrid_next_result(3) function is used to get results of next query if multiple SQL statements are executed and CUBRID_EXEC_QUERY_ALL flag is set upon cubrid_execute(3). PARAMETERS
o $result -$result comes from a call to cubrid_execute(3) RETURN VALUES
TRUE, when process is successful. FALSE, when process is unsuccessful. EXAMPLES
Example #1 cubrid_next_result(3) example <?php $conn = cubrid_connect("127.0.0.1", 33000, "demodb", "dba"); $sql_stmt = "SELECT * FROM code; SELECT * FROM history WHERE host_year=2004 AND event_code=20281"; $res = cubrid_execute($conn, $sql_stmt, CUBRID_EXEC_QUERY_ALL); get_result_info($res); cubrid_next_result($res); get_result_info($res); function get_result_info($req) { printf(" ------------ get_result_info -------------------- "); $row_num = cubrid_num_rows($req); $col_num = cubrid_num_cols($req); $column_name_list = cubrid_column_names($req); $column_type_list = cubrid_column_types($req); $column_last_name = cubrid_field_name($req, $col_num - 1); $column_last_table = cubrid_field_table($req, $col_num - 1); $column_last_type = cubrid_field_type($req, $col_num - 1); $column_last_len = cubrid_field_len($req, $col_num - 1); $column_1_flags = cubrid_field_flags($req, 1); printf("%-30s %d ", "Row count:", $row_num); printf("%-30s %d ", "Column count:", $col_num); printf(" "); printf("%-30s %-30s %-15s ", "Column Names", "Column Types", "Column Len"); printf("------------------------------------------------------------------------------ "); $size = count($column_name_list); for($i = 0; $i < $size; $i++) { $column_len = cubrid_field_len($req, $i); printf("%-30s %-30s %-15s ", $column_name_list[$i], $column_type_list[$i], $column_len); } printf(" "); printf("%-30s %s ", "Last Column Name:", $column_last_name); printf("%-30s %s ", "Last Column Table:", $column_last_table); printf("%-30s %s ", "Last Column Type:", $column_last_type); printf("%-30s %d ", "Last Column Len:", $column_last_len); printf("%-30s %s ", "Second Column Flags:", $column_1_flags); printf(" "); } ?> The above example will output: ------------ get_result_info -------------------- Row count: 6 Column count: 2 Column Names Column Types Column Len ------------------------------------------------------------------------------ s_name char 1 f_name varchar 6 Last Column Name: f_name Last Column Table: code Last Column Type: varchar Last Column Len: 6 Second Column Flags: ------------ get_result_info -------------------- Row count: 4 Column count: 5 Column Names Column Types Column Len ------------------------------------------------------------------------------ event_code integer 11 athlete varchar 40 host_year integer 11 score varchar 10 unit varchar 5 Last Column Name: unit Last Column Table: history Last Column Type: varchar Last Column Len: 5 Second Column Flags: not_null primary_key unique_key SEE ALSO
cubrid_execute(3). PHP Documentation Group CUBRID_NEXT_RESULT(3)
All times are GMT -4. The time now is 03:55 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy