The script snippet looks garbled. It sounds like the wildcard in the pattern got expanded by the shell at some point. You need more double quotes where it happens
But aren't you making it too complicated? How about
Code:
while IFS=, read pattern rest
do
egrep "$pattern" $source_file
done < p
Juha
This User Gave Thanks to Juha Nurmela For This Post:
Is there anyway you can grep using multiple wildcards? When I run the below line the results return fine;
grep 12345 /usr/local/production/soccermatchplus/distributor/clients/*/out/fixtures.xml | awk -F/ '{print $8}'
However ideally, I need it to grep for;
grep 12345... (3 Replies)
I need to pass a parameter that will then be grepped.
I need it to grep /paramater and then have a space
so if 123 was passed my grep would be grep '/123 ' sample.log
this works fine from the command line
but when i try and set it searchThis="/$2 "
and then run grep $searchThis... (6 Replies)
Hello,
I would like for the user to input the date for a particular log file, then have the input sent to a variable, which is then used via grep to extra the logs for the specific date the user request.
I did some searching, but I still don't understand why I'm not seeing any result.
... (4 Replies)
Hi,
I have an HTML form through which I get some text as input. i need to run a shell script say script.sh inside a perl-cgi script named main_cgi.sh on the form input.
I want to write the contents of the form in a file and then perform some command line operations like grep, cat on the text... (0 Replies)
Hello,
I have a text file which contains a list of strings which I want to grep from another file where these strings occur and print out only these lines.
I had earlier used the grep command
where File1 was the file containing the strings to be grepped (Source File) and File2 the Target File... (4 Replies)
I have a script which reads a number out of a log file. The pertinent line is this:
cat /tmp/listofnumbers
When I run cat /tmp/listofnumbers what I am seeing is on each line.
I am trying to make the script read from that file and grep for a variable like the following line should do:
... (4 Replies)
Hello,
I have a data in file 1
2000000024776
2000000026979
2000000033355
2000000036309
2000000041291
2000000042679
2000000067221
and in file 2 its like this
2000000024776 16
2000000026979 16
2000000033355 16 (2 Replies)
Hi There, Good Day !!
I have txt file containing data in the below format. There are many lines, here i have mentioned for example.
cat remo.txt
2/3/2017 file1
3/4/2016 file2
6/6/2015 file5
1/1/2018 file3
4/3/2014 file4
-
-
-
I need to grep the file names for given date rage... (11 Replies)
Dear Forum members,
I am having trouble getting the complete filename (and directory path) in a variable.
Output directory mentioned in the code have three files:
DISPLAY_CITY_DETAILS_15-05-2019-08-29-26_MIGRATE_london.out
DISPLAY_CITY_DETAILS_15-05-2019-08-29-26_MIGRATE_paris.out... (4 Replies)
Im trying to search for a single variable in the first field and from that output use awk to extract out the lines that contain a value less than a value stored in another variable. Both the variables are associated with each other.
Any guidance is appreciated.
File that contains the... (6 Replies)
Discussion started by: ncwxpanther
6 Replies
LEARN ABOUT MOJAVE
zipgrep
ZIPGREP(1L)ZIPGREP(1L)NAME
zipgrep - search files in a ZIP archive for lines matching a pattern
SYNOPSIS
zipgrep [egrep_options] pattern file[.zip] [file(s) ...] [-x xfile(s) ...]
DESCRIPTION
zipgrep will search files within a ZIP archive for lines matching the given string or pattern. zipgrep is a shell script and requires
egrep(1) and unzip(1L) to function. Its output is identical to that of egrep(1).
ARGUMENTS
pattern
The pattern to be located within a ZIP archive. Any string or regular expression accepted by egrep(1) may be used. file[.zip] Path
of the ZIP archive. (Wildcard expressions for the ZIP archive name are not supported.) If the literal filename is not found, the
suffix .zip is appended. Note that self-extracting ZIP files are supported, as with any other ZIP archive; just specify the .exe
suffix (if any) explicitly.
[file(s)]
An optional list of archive members to be processed, separated by spaces. If no member files are specified, all members of the ZIP
archive are searched. Regular expressions (wildcards) may be used to match multiple members:
* matches a sequence of 0 or more characters
? matches exactly 1 character
[...] matches any single character found inside the brackets; ranges are specified by a beginning character, a hyphen, and an end-
ing character. If an exclamation point or a caret (`!' or `^') follows the left bracket, then the range of characters within
the brackets is complemented (that is, anything except the characters inside the brackets is considered a match).
(Be sure to quote any character that might otherwise be interpreted or modified by the operating system.)
[-x xfile(s)]
An optional list of archive members to be excluded from processing. Since wildcard characters match directory separators (`/'),
this option may be used to exclude any files that are in subdirectories. For example, ``zipgrep grumpy foo *.[ch] -x */*'' would
search for the string ``grumpy'' in all C source files in the main directory of the ``foo'' archive, but none in any subdirectories.
Without the -x option, all C source files in all directories within the zipfile would be searched.
OPTIONS
All options prior to the ZIP archive filename are passed to egrep(1).
SEE ALSO egrep(1), unzip(1L), zip(1L), funzip(1L), zipcloak(1L), zipinfo(1L), zipnote(1L), zipsplit(1L)URL
The Info-ZIP home page is currently at
http://www.info-zip.org/pub/infozip/
or
ftp://ftp.info-zip.org/pub/infozip/ .
AUTHORS
zipgrep was written by Jean-loup Gailly.
Info-ZIP 20 April 2009 ZIPGREP(1L)
10-10-2016
