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Full Discussion: How do I use the cut command to only print the directories?
Top Forums UNIX for Beginners Questions & Answers How do I use the cut command to only print the directories? Post 302983123 by RudiC on Thursday 6th of October 2016 02:23:15 PM
Old 10-06-2016
For two reasons, cut may not be the tool of choice here:
- you can't select by field, as a non-predictable number of spaces in the owner, group, and size field doesn't allow to reliably select the file name field. translating spaces can deteriorate file names, btw.
- you can't select by character/byte position, as esp. the size field can be adapted to large numbers.

So you might need to fall back to a text utility as sed, awk, and so on.
But, la | awk '{print $9}' wouldn't help either, in case of file name containing spaces. You'd need to resort to sth like
Code:
la | awk '{sub ($1 FS $2 FS ".*" $8 FS, _); print}'

, but that also might still need some polishing.
This User Gave Thanks to RudiC For This Post:
rbatte1
 

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LEARN ABOUT X11R4

cut

CUT(1)                                                             User Commands                                                            CUT(1)

NAME

       cut - remove sections from each line of files

SYNOPSIS

       cut OPTION... [FILE]...

DESCRIPTION

       Print selected parts of lines from each FILE to standard output.

       With no FILE, or when FILE is -, read standard input.

       Mandatory arguments to long options are mandatory for short options too.

       -b, --bytes=LIST
              select only these bytes

       -c, --characters=LIST
              select only these characters

       -d, --delimiter=DELIM
              use DELIM instead of TAB for field delimiter

       -f, --fields=LIST
              select only these fields;  also print any line that contains no delimiter character, unless the -s option is specified

       -n     (ignored)

       --complement
              complement the set of selected bytes, characters or fields

       -s, --only-delimited
              do not print lines not containing delimiters

       --output-delimiter=STRING
              use STRING as the output delimiter the default is to use the input delimiter

       -z, --zero-terminated
              line delimiter is NUL, not newline

       --help display this help and exit

       --version
              output version information and exit

       Use  one,  and only one of -b, -c or -f.  Each LIST is made up of one range, or many ranges separated by commas.  Selected input is written
       in the same order that it is read, and is written exactly once.  Each range is one of:

       N      N'th byte, character or field, counted from 1

       N-     from N'th byte, character or field, to end of line

       N-M    from N'th to M'th (included) byte, character or field

       -M     from first to M'th (included) byte, character or field

AUTHOR

       Written by David M. Ihnat, David MacKenzie, and Jim Meyering.

REPORTING BUGS

       GNU coreutils online help: <http://www.gnu.org/software/coreutils/>
       Report cut translation bugs to <http://translationproject.org/team/>

COPYRIGHT

       Copyright (C) 2017 Free Software Foundation, Inc.  License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>.
       This is free software: you are free to change and redistribute it.  There is NO WARRANTY, to the extent permitted by law.

SEE ALSO

       Full documentation at: <http://www.gnu.org/software/coreutils/cut>
       or available locally via: info '(coreutils) cut invocation'

GNU coreutils 8.28                                                 January 2018                                                             CUT(1)
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