Sponsored Content
Top Forums UNIX for Beginners Questions & Answers How do I use the cut command to only print the directories? Post 302983123 by RudiC on Thursday 6th of October 2016 02:23:15 PM
Old 10-06-2016
For two reasons, cut may not be the tool of choice here:
- you can't select by field, as a non-predictable number of spaces in the owner, group, and size field doesn't allow to reliably select the file name field. translating spaces can deteriorate file names, btw.
- you can't select by character/byte position, as esp. the size field can be adapted to large numbers.

So you might need to fall back to a text utility as sed, awk, and so on.
But, la | awk '{print $9}' wouldn't help either, in case of file name containing spaces. You'd need to resort to sth like
Code:
la | awk '{sub ($1 FS $2 FS ".*" $8 FS, _); print}'

, but that also might still need some polishing.
This User Gave Thanks to RudiC For This Post:
 

9 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Need help with Cut command

Hi I am using 'find' on a particular directory which has some subdirectories too,so when I search for .txt files from the parent directory, it gives all files that matches the pattern in the parent aswellas in the sub directories . eg: Iam at /a/b/c where c has many other directories in it ... (7 Replies)
Discussion started by: jagadish_gaddam
7 Replies

2. UNIX for Dummies Questions & Answers

cut and print part of a string

I have a file that contains: yahoo.com.23456 web.log.common.us.gov.8675 192.168.1.55.34443 john-doe.about.com.22233 64.222.3.4.120 sunny.ca.4442 how can i remove the strings after the last dot (.) and reprint the file? Thanks. (3 Replies)
Discussion started by: apalex
3 Replies

3. Shell Programming and Scripting

Cut Command error cut: Bad range

Hi Can anyone what I am doing wrong while using cut command. for f in *.log do logfilename=$f Log "Log file Name: $logfilename" logfile1=`basename $logfilename .log` flength=${#logfile1} Log "file length $flength" from_length=$(($flength - 15)) Log "from... (2 Replies)
Discussion started by: dgmm
2 Replies

4. UNIX for Dummies Questions & Answers

Using grep command to find the pattern of text in all directories and sub-directories.

Hi all, Using grep command, i want to find the pattern of text in all directories and sub-directories. e.g: if i want to search for a pattern named "parmeter", i used the command grep -i "param" ../* is this correct? (1 Reply)
Discussion started by: vinothrajan55
1 Replies

5. Shell Programming and Scripting

Print the whole line which contains the result of the command cut

Hey everyone I have a file 'agenda' which contains: Object Day Month Year Birthday 09 02 2012 i want to extract from a script the line which contains the day the user typed. for example if he type 09 the line is showed using... (4 Replies)
Discussion started by: Goldstein
4 Replies

6. Shell Programming and Scripting

Print path files in different directories

Hi guys :) First of all Happy New Year :) so i dont know if my doubt its already here posted by other person ... i need to print to one file the path of few files that are in different directories, like this: directory muscle ATP6.aa.muscle.fasta COX1.aa.muscle.fasta . . . ... (2 Replies)
Discussion started by: andreia
2 Replies

7. UNIX for Dummies Questions & Answers

Cut pid from ps using cut command

hay i am trying to get JUST the PID from the ps command. my command line is: ps -ef | grep "mintty" | cut -d' ' -f2 but i get an empty line. i assume that the delimiter is not just one space character, but can't figure out what should i do in order to do that. i know i can use awk or cut... (8 Replies)
Discussion started by: ran ber
8 Replies

8. UNIX for Dummies Questions & Answers

Print/cut/grep/sed/ date yyyymmdd on the filename only.

I have this filename "RBD_EXTRACT_a3468_d20131118.tar.gz" and I would like print out the "yyyymmdd" only. I use this command below, but if different command like cut or print....etc. Thanks ls RBD_EXTRACT* | sed 's/.*\(........\).tar.gz$/\1/' > test.txt (9 Replies)
Discussion started by: dotran
9 Replies

9. UNIX for Beginners Questions & Answers

Cut command: can't make it cut fields

I'm a complete beginner in UNIX (and not a computer science student either), just undergoing a tutoring course. Trying to replicate the instructions on my own I directed output of the ls listing command (lists all files of my home directory ) to My_dir.tsv file (see the screenshot) to make use of... (9 Replies)
Discussion started by: scrutinizerix
9 Replies
CUT(1)							    BSD General Commands Manual 						    CUT(1)

NAME
cut -- cut out selected portions of each line of a file SYNOPSIS
cut -b list [-n] [file ...] cut -c list [file ...] cut -f list [-w | -d delim] [-s] [file ...] DESCRIPTION
The cut utility cuts out selected portions of each line (as specified by list) from each file and writes them to the standard output. If no file arguments are specified, or a file argument is a single dash ('-'), cut reads from the standard input. The items specified by list can be in terms of column position or in terms of fields delimited by a special character. Column and field numbering start from 1. The list option argument is a comma or whitespace separated set of increasing numbers and/or number ranges. Number ranges consist of a num- ber, a dash ('-'), and a second number and select the columns or fields from the first number to the second, inclusive. Numbers or number ranges may be preceded by a dash, which selects all columns or fields from 1 to the last number. Numbers or number ranges may be followed by a dash, which selects all columns or fields from the last number to the end of the line. Numbers and number ranges may be repeated, overlap- ping, and in any order. It is not an error to select columns or fields not present in the input line. The options are as follows: -b list The list specifies byte positions. -c list The list specifies character positions. -d delim Use delim as the field delimiter character instead of the tab character. -f list The list specifies fields, separated in the input by the field delimiter character (see the -d option). Output fields are separated by a single occurrence of the field delimiter character. -n Do not split multi-byte characters. Characters will only be output if at least one byte is selected, and, after a prefix of zero or more unselected bytes, the rest of the bytes that form the character are selected. -s Suppress lines with no field delimiter characters. Unless specified, lines with no delimiters are passed through unmodified. -w Use whitespace (spaces and tabs) as the delimiter. Consecutive spaces and tabs count as one single field separator. ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of cut as described in environ(7). EXIT STATUS
The cut utility exits 0 on success, and >0 if an error occurs. EXAMPLES
Extract users' login names and shells from the system passwd(5) file as ``name:shell'' pairs: cut -d : -f 1,7 /etc/passwd Show the names and login times of the currently logged in users: who | cut -c 1-16,26-38 SEE ALSO
colrm(1), paste(1) STANDARDS
The cut utility conforms to IEEE Std 1003.2-1992 (``POSIX.2''). HISTORY
A cut command appeared in AT&T System III UNIX. BSD
August 8, 2012 BSD
All times are GMT -4. The time now is 04:33 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy