Hi
I have a log file (say log.txt). I have to search for a line which has the string ( say ERROR) in the log file and copy 15 lines after this into another file (say error.txt). Can someone give me the code and this has to be in PERL
Thanks in advance
Ammu (3 Replies)
Ok I have a file with hundreds of lines, four columns, space delimited, TESTB.TXT for example
TESTB.TXT
---
AA ZZ 12 34
BB YY 56 78
CC XX 91 23
DD VV 45 67
---
I want a new file that has 7 columns, the first four are identical, and the next 3 are the last three of the next line...so... (5 Replies)
I'm trying to read an xml file and copy it line by line to another file and want to preserve the tabs.
What i'm trying to do is if I get to a certain line in the xml, I'm going to check to see if the next line is specifically what I want. If it's not, then I want to insert a single line of text... (4 Replies)
I generally use yy to copy a line and then p to paste the line at end of current line.
But is there a way to paste the copied line in concatenation with the current line with out going to next line. (3 Replies)
How would you do vim copy line and paste at the beginning, middle, and end of another line. I know yy copies the whole line and p pastes the whole line, but on its own separate line. Sometimes I would like to copy a line to the beginning, middle, or end of another line. I would think this would be... (3 Replies)
I am trying to delete lines in archived Apache httpd logs
Each line has the pattern:
<ip-address> - - <date-time> <document-request-URL> <http-response> <size-of-req'd-doc> <referring-document-URL>
This pattern is shown in the example of 6 lines from the log in the code box below. These 6... (1 Reply)
Hi,
I have lines that have pattern like this.
1)
productFamilyGroupIndex < Local.ProductFamilyGroup.capacity))
and
2)
if (local.getProductFamilyGroup().size() >= Local.ProductFamilyGroup.
capacity)
So, If I need to find the pattern
grep '\(< \|>= \)Local.*capacity'... (4 Replies)
Help,
I have a text file which looks like
disco 5674536
3456 jambo
disco 453678
4578 jambo
I would like to have an output which looks like below
disco 3456 disco 4578 (4 Replies)
Hi,
I have an XML file and I am tring to extract some data form it, after lot of data cleaning process, I ended up with an issue, and need your urgent support.
my current input data in below format:
<Node>xxxxxx
<Node>yyyyy</Node>
<Node>zzzzzz
<Node>12345</node>
I need... (9 Replies)
Discussion started by: rramkrishnas
9 Replies
LEARN ABOUT DEBIAN
print_time_table
PARSE_TIME(3) BSD Library Functions Manual PARSE_TIME(3)NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals
LIBRARY
The roken library (libroken, -lroken)
SYNOPSIS
#include <parse_time.h>
int
parse_time(const char *timespec, const char *def_unit);
void
print_time_table(FILE *f);
size_t
unparse_time(int seconds, char *buf, size_t len);
size_t
unparse_time_approx(int seconds, char *buf, size_t len);
DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number
unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit.
The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as
human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units.
print_time_table() prints a descriptive list of available units on the passed file descriptor.
The possible units include:
second, s
minute, m
hour, h
day
week seven days
month 30 days
year 365 days
Units names can be arbitrarily abbreviated (as long as they are unique).
RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and
unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the
string was too short and some of the printed characters were discarded.
EXAMPLES
#include <stdio.h>
#include <parse_time.h>
int
main(int argc, char **argv)
{
int i;
int result;
char buf[128];
print_time_table(stdout);
for (i = 1; i < argc; i++) {
result = parse_time(argv[i], "second");
if(result == -1) {
fprintf(stderr, "%s: parse error
", argv[i]);
continue;
}
printf("--
");
printf("parse_time = %d
", result);
unparse_time(result, buf, sizeof(buf));
printf("unparse_time = %s
", buf);
unparse_time_approx(result, buf, sizeof(buf));
printf("unparse_time_approx = %s
", buf);
}
return 0;
}
$ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s"
1 year = 365 days
1 month = 30 days
1 week = 7 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 second
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 31535999
unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds
unparse_time_approx = 12 months
BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a
hack for English plural forms. If these functions are ever localised, this scheme will have to change.
HEIMDAL October 31, 2004 HEIMDAL