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Full Discussion: A $(( expression )) bug?
Top Forums UNIX for Advanced & Expert Users A $(( expression )) bug? Post 302982332 by RudiC on Wednesday 28th of September 2016 05:13:59 AM
Old 09-28-2016
The
Quote:
Arithmetic Expansion
Arithmetic expansion allows the evaluation of an arithmetic expression and the substitution of the result. The format for arithmetic expansion is:

$((expression))

The old format $[expression] is deprecated and will be removed in upcoming versions of bash.

The expression is treated as if it were within double quotes, but a double quote inside the parentheses is not treated specially. All tokens in the expression undergo parameter and variable expansion, command substitution, and quote removal.
(c.f. man bash) is available in recent shells only, not in sh. As you can see, variable expansion is done implicitly, no $ nor ${} necessary. Your message above is informative, not an error.

Last edited by RudiC; 09-28-2016 at 01:40 PM.. Reason: added the man bash reference
 

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let(1)                                                             User Commands                                                            let(1)

NAME
let - shell built-in function to evaluate one or more arithmetic expressions SYNOPSIS
ksh let arg... DESCRIPTION
ksh Each arg is a separate "arithmetic expression" to be evaluated. EXIT STATUS
The following exit values are returned: 0 The value of the last expression is non-zero. 1 The value of the last expression is zero. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWcsu | +-----------------------------+-----------------------------+ SEE ALSO
ksh(1), set(1), typeset(1), attributes(5) SunOS 5.10 15 Apr 1994 let(1)
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