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Top Forums UNIX for Beginners Questions & Answers Concatenate column values when header is Matching from multiple files Post 302982109 by RavinderSingh13 on Saturday 24th of September 2016 01:52:43 AM
Old 09-24-2016
Hello Nina,

So number of columns were not mentioned before so solution was according to it, so following may help you with dynamic number of columns but condition is Input_files should have same number of columns(based on row vice), if this condition is TRUE(which seems to be as per your post) then following may help you in same. Let's say following are the Input_files.
Code:
cat a.txt
Name 9/1 9/2
X 1 7 7 8 9 10 12 12 12 12 12 13
y 2 8 3 4 5 6 7 8 8 9 1 212 12 12
z 3 9 1 1 2
a 4 10 1
b 5 11
c 6 12 12 13 14

cat b.txt
Name 9/1 9/2
X 1 7 7 8 9 10 12 12 12 12 12 13
y 22 4 13 2 53 26 17 18 82 19 111 12 13 4
z 3 9 1 1 2
a 4 10 1
b 5 11
c 6 12 12 13 14

cat c.txt
Name 9/1 9/2
X 1 7 7 8 9 10 12 12 12 12 12 13
y 2 8 3 4 5 6 7 8 8 9 1 212 12 12
z 3 9 1 1 2
a 4 10 1
b 5 11
c 6 12 12 13 14

Then following is the code for same.
Code:
paste *.txt | awk 'function get(field){q=NF/3;for(i=field;i<=NF;i+=q){$field=i>field?$field "/" $i:$field;}} NR>1{for(j=2;j<=NF/3;j++){get(j)};for(j=NF/3+1;j<=NF;j++){$j=""};sub(/[[:space:]]+$/,X,$0);print}'

Output will be as follows.
Code:
X 1/1/1 7/7/7 7/7/7 8/8/8 9/9/9 10/10/10 12/12/12 12/12/12 12/12/12 12/12/12 12/12/12 13/13/13                          
y 2/22/2 8/4/8 3/13/3 4/2/4 5/53/5 6/26/6 7/17/7 8/18/8 8/82/8 9/19/9 1/111/1 212/12/212 12/13/12 12/4/12                              
z 3/3/3 9/9/9 1/1/1 1/1/1 2/2/2            
a 4/4/4 10/10/10 1/1/1        
b 5/5/5 11/11/11      
c 6/6/6 12/12/12 12/12/12 13/13/13 14/14/14

Also in above code wherever I have used NF/3 so it is because of 3 Input_files are there if they vary in numbers then you could change according to their number. Kindly do let me know if this helps you or if you have any issues on same.
EDIT: Adding a non-one liner form of solution too here.
Code:
paste *.txt | awk 'function get(field){
					q=NF/3;
					for(i=field;i<=NF;i+=q){
								$field=i>field?$field "/" $i:$field;
							       }
                                      } 
                   NR>1               {
					for(j=2;j<=NF/3;j++)   {
								get(j)
                                                               };
					for(j=NF/3+1;j<=NF;j++){
								$j=""
							       };
                                        sub(/[[:space:]]+$/,X,$0);
					print
 				      }
                  '

Thanks,
R. Singh

Last edited by RavinderSingh13; 09-24-2016 at 03:06 AM.. Reason: Adding a non-one liner form of solution on same too succcessfully now.
This User Gave Thanks to RavinderSingh13 For This Post:
 

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