I'm racking my brain on this one! :(
I have a list like this:
Paul 20
Paul 25
Paul 30
Frank 10
Julie 15
Julie 13
etc, etc...
I've been trying to figure out a way to have the output display the name in the first column ONCE and add the numbers in the second column and display that... (2 Replies)
How do I grep/check the on-hand value on the second line of show_prod script below? In this case it's a "3".
So if it's > 0, then run_this, otherwise, quit.
> ./show_prod
Product Status Onhand Price
shoe OK 3 1.1 (6 Replies)
Hi friends,
My file is like:
Second file is :
I need to print the rows present in file one, but in order present in second file....I used
while read gh;do
awk ' $1=="' $gh'" {print >> FILENAME"output"} ' cat listoffirstfile
done < secondfile
but the output I am... (14 Replies)
I have a csv file with occasional multiple entries in the second column.
111111,104,07-24-2011,3.15,N,
222222,020 140,07-24-2011,10.00,N,I want the result
111111,104,07-24-2011,3.15,N,
222222,020,07-24-2011,10.00,N,
222222,140,07-24-2011,10.00,N,
I know I can get the output of the second... (5 Replies)
Hi experts,
My csv file looks like this
U;cake;michael;temp;;;;
U;bread;john;temp;;;;
U;cocktails;sarah;temp;;;;
I'd like to change the value fo 2nd column to cf+random number , which will look maybe something like this
U;cf20187;michael;temp;;;;
U;cf8926;john;temp;;;;... (7 Replies)
Hi
I have 5 columns like this
a b c d e
f g h i j
k l m n o
From 2nd column till the 5th column of every record, I would like to transpose them as rows, so my output file contains only one row
a
b
c
d
e
f
g
h
i
j (9 Replies)
I have the code for the below things..
File1 has the content as below
8859 0 subscriberCreate
18 0 subscriberPaymentMethodChange
1650 0 subscriberProfileUpdate
7668 0 subscriberStatusChange
13 4020100 subscriberProfileUpdate
1 4020129 subscriberStatusChange
2 4020307 subscriberCreate
8831... (5 Replies)
hi
I have 2 file with more than 10 columns for both
1st file
apple,0,0,0......
orange,1,2,3.....
mango,2,4,5.....
2nd file
apple,2,3,4,5,6,7...
orange,2,3,4,5,6,8...
watermerlon,2,3,4,5,6,abc...
mango,5,6,7,4,6,def.... (1 Reply)
Discussion started by: tententen
1 Replies
LEARN ABOUT REDHAT
logfile
LOGFILE(1) mrtg LOGFILE(1)NAME
logfile - description of the mrtg-2 logfile format
SYNOPSIS
This document provides a description of the contents of the mrtg-2 logfile.
OVERVIEW
The logfile consists of two main sections. A very short one at the beginning:
The first Line
It stores the traffic counters from the most recent run of mrtg
The rest of the File
Stores past traffic rate averates and maxima at increassing intervals
The first number on each line is a unix time stamp. It represents the number of seconds since 1970.
DETAILS
The first Line
The first line has 3 numbers which are:
A (1st column)
A timestamp of when MRTG last ran for this interface. The timestamp is the number of non-skip seconds passed since the standard UNIX
"epoch" of midnight on 1st of January 1970 GMT.
B (2nd column)
The "incoming bytes counter" value.
C (3rd column)
The "outgoing bytes counter" value.
The rest of the File
The second and remaining lines of the file 5 numbers which are:
A (1st column)
The Unix timestamp for the point in time the data on this line is relevant. Note that the interval between timestamps increases as you
prograss through the file. At first it is 5 minutes and at the end it is one day between two lines.
This timestamp may be converted in EXCEL by using the following formula:
=(x+y)/86400+DATE(1970,1,1)
you can also ask perl to help by typing
perl -e 'print scalar localtime(x),"
"'
x is the unix timestamp and y is the offset in seconds from UTC. (Perl knows y).
B (2nd column)
The average incoming transfer rate in bytes per second. This is valid for the time between the A value of the current line and the A
value of the previous line.
C (3rd column)
The average outgoing transfer rate in bytes per second since the previous measurement.
D (4th column)
The maximum incoming transfer rate in bytes per second for the current interval. This is calculated from all the updates which have
occured in the current interval. If the current interval is 1 hour, and updates have occured every 5 minutes, it will be the biggest 5
minute transferrate seen during the hour.
E (5th column)
The maximum outgoing transfer rate in bytes per second for the current interval.
AUTHOR
Butch Kemper <kemper@bihs.net> and Tobias Oetiker <oetiker@ee.ethz.ch>
3rd Berkeley Distribution 2.9.17 LOGFILE(1)