I reopens the post because I still have a few questions concerning my script that it below :
Code:
declare -a missing
for name in $fichier1 $fichier2 $fichier3 $fichier4 $fichier5 $fichier6
do
[[ -e $name ]] || missing[${#missing[*]}]=$name
done
if (( ${#missing[*]} == 0 ))
then
echo -e "\nDate : $date_form2\nFile : $name_files\nHeight : $height_files\n"
echo -e "Date : $date_form2\nFile : $name_files1\nHeight : $height_files1\n"
echo -e "Date : $date_form2\nFile : $name_files2\nHeight : $height_files2\n"
echo -e "Date : $date_form2\nFile : $name_files3\nHeight : $height_files3\n"
echo -e "Date : $date_form2\nFile : $name_files4\nHeight : $height_files4\n"
echo -e "Date : $date_form2\nFile : "$name_files5"\nHeight : $height_files5"
else
echo "Missing: " ${missing[*]}
fi
echo -e "\nDisk Used : $disk_used\nDisk Available : $disk_available\nDisk Used In Percent : $disk_percent\n"
exit 0
here, It work like I want but in the "else" section I would like the same thing that in the "then" section but with the path of missing file instead of the "$name_fileX".
I would like this ouput for example (file5 missing):
Code:
Date : 2016-09-19
File : name_files
Height : 100K
Date : 2016-09-19
File : name_files1
Height : 160K
Date : 2016-09-19
File : name_files2
Height : 4.0K
Date : 2016-09-19
File : name_files3
Height : 236K
Date : 2016-09-19
File : name_files4
Height : 4.0K
Date : 2016-09-19
File : Missing: name_file5
Height : 4.0K
Disk Used : 39M
Disk Available : 185M
Disk Used In Percent : 18%
Here, While hoping to have been clearly.... thanks by advance
Last edited by Arnaudh78; 09-20-2016 at 03:29 PM..
Hello,
In my shell program, I need to test for a specific size of a text file before it can be imported into an oracle table.
If the size is less than that number, my program should stop processing. What is the correct command to do this test?
Thanks! (1 Reply)
Using dd or similar tools to recover data from 2 damaged cdroms, I need a way to then combine the 2 files, 1 from each cd, and make a good file: this all result from finding that certain cd's tops scratch easily even when using the "proper" cd markers, hence making the file useless, however the... (1 Reply)
Hi Experts,
by mistake i deleted some files that are very important to the project.
is there any way that i can recover those files,there is no backup for that but the details of the file we know.
This will be a great help.
Thanks (5 Replies)
Hi Guys
I accidently deleted a directory( and the files in it) in unix using 'rm -rf' :)
Is there any procedure/script/command to recover the same?
Your help is highly apperciated
-thanks
Subramanya (1 Reply)
Hi,
By mistake, executed the following command :
rm -rf *
and ALL files got deleted.
But I need to get back these files as they are very very important.
Please help me how to recover this file. Its Urgent for me please.
Thanks in advance. (6 Replies)
Discussion started by: unx100
6 Replies
LEARN ABOUT PHP
datefmt_is_lenient
DATEFMT_IS_LENIENT(3) 1 DATEFMT_IS_LENIENT(3)IntlDateFormatter::isLenient - Get the lenient used for the IntlDateFormatter
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::isLenient (void )
DESCRIPTION
Procedural style
bool datefmt_is_lenient (IntlDateFormatter $fmt)
Check if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly.
PARAMETERS
o $fmt
- The formatter resource.
RETURN VALUES
TRUE if parser is lenient, FALSE if parser is strict. By default the parser is lenient.
EXAMPLES
Example #1
datefmt_is_lenient(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/mm/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt,false);
echo 'Now lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
"dd/mm/yyyy"
);
echo "lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0){
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo 'Now lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
The above example will output:
lenient of the formatter is : TRUE
Trying to do parse('35/13/1971').
Result is : -2147483
Now lenient of the formatter is : FALSE
Trying to do parse('35/13/1971').
Result is :
Error_msg is : Date parsing failed: U_PARSE_ERROR
Error_code is : 9
SEE ALSO datefmt_set_lenient(3), datefmt_create(3).
PHP Documentation Group DATEFMT_IS_LENIENT(3)
09-20-2016
thanks by advance 