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Full Discussion: Exclude variable from a file
Top Forums Shell Programming and Scripting Exclude variable from a file Post 302981551 by coppuca on Wednesday 14th of September 2016 02:01:52 PM
Old 09-14-2016
Exclude variable from a file

Hello,

I have a list of patterns which I'd like to exclude from a file. I tried to do

Code:
while read line
do
grep -v $line file >> new.file
done < mylist

But obviously it won't work. It only works for just grep. I know I can do:

Code:
grep -Ev 'pattern1|pattern2|...' myfile

but my list is very long. Is there any other elegant way to do it? I don't need to use grep, anything else would be also fine.

Thank you!
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep is used to invoke the grep on compress'ed or gzip'ed files. All options specified are passed directly to grep. If no file is speci- fied, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If zgrep is invoked as zegrep or zfgrep then egrep or fgrep is used instead of grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. For example: for sh: GREP=fgrep zgrep string files for csh: (setenv GREP fgrep; zgrep string files) AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), egrep(1), fgrep(1), zdiff(1), zmore(1), znew(1), zforce(1), gzip(1), gzexe(1) ZGREP(1)
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