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Top Forums Shell Programming and Scripting To substitute multiple variable by their content in a file Post 302981523 by dae on Wednesday 14th of September 2016 09:39:37 AM
Old 09-14-2016
To substitute multiple variable by their content in a file

Dear All,

I would like to instantiate a "pattern file" substituting "variable name" by their content.

Saying, we have:

1/ a "pattern file" containing different "variable name", the first character of the "variable name" is "@":

Code:
[x004191a@xsnl11p317a modl]$ cat TPTModl.txt
                              DEFINE OPERATOR FILE_READER_@OBJ_TBLNAME_CD
                              DESCRIPTION 'TERADATA PARALLEL TRANSPORTER DATA CONNECTOR PRODUCER OPERATOR'
                              TYPE DATACONNECTOR PRODUCER
                              SCHEMA SCHEMA_@OBJ_TBLNAME_CD
                              ATTRIBUTES
                            (
                              DirectoryPath                = '@DirectoryPath'
                            , ArchiveDirectoryPath         = '@ArchiveDirectoryPath'
                            , FileName                     = '@OBJFLOWPARM_FILEPATTERNDEFN_CD'
                            , Format                       = 'DELIMITED'
                            , TextDelimiter                = '@OBJFLOWPARM_FILETEXTDELIMITER_CD'
                            , EnableScan                   = 'Y'
                            , IndicatorMode                = 'N'
                            , TrimTrailingBlanks           = 'Y'
                            , TrimLeadingBlanks            = 'Y'
                            , OpenMode                     = 'Read'
                            );

2/ a variable with the list of the "variable name" with their value:

Code:
[x004191a@xsnl11p317a tmp]$ echo "$var"
@OBJ_DBNAME_CD:ABCD
@OBJ_TBLNAME_CD:EFGH
@OBJFLOWPARM_FILEPATTERNDEFN_CD:*_VERSFLDR.csv
@OBJFLOWPARM_FILETEXTDELIMITER_CD:$$

How would it be possible to produce an output file from the pattern input file with all the replacement done ?

Thanks a lot for your help and kind attention,

Didier.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for a pattern SYNOPSIS
grep [ option ... ] pattern [ file ... ] DESCRIPTION
Grep searches the input files (standard input default) for lines (with newlines excluded) that match the pattern, a regular expression as defined in regexp(6). Normally, each line matching the pattern is `selected', and each selected line is copied to the standard output. The options are -c Print only a count of matching lines. -h Do not print file name tags (headers) with output lines. -i Ignore alphabetic case distinctions. The implementation folds into lower case all letters in the pattern and input before interpre- tation. Matched lines are printed in their original form. -l (ell) Print the names of files with selected lines; don't print the lines. -L Print the names of files with no selected lines; the converse of -l. -n Mark each printed line with its line number counted in its file. -s Produce no output, but return status. -v Reverse: print lines that do not match the pattern. Output lines are tagged by file name when there is more than one input file. (To force this tagging, include /dev/null as a file name argument.) Care should be taken when using the shell metacharacters $*[^|()= and newline in pattern; it is safest to enclose the entire expression in single quotes '...'. SOURCE
/sys/src/cmd/grep.c SEE ALSO
ed(1), awk(1), sed(1), sam(1), regexp(6) DIAGNOSTICS
Exit status is null if any lines are selected, or non-null when no lines are selected or an error occurs. GREP(1)
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