To substitute multiple variable by their content in a file Post: 302981523

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Top Forums Shell Programming and Scripting To substitute multiple variable by their content in a file Post 302981523 by dae on Wednesday 14th of September 2016 09:39:37 AM

09-14-2016

Registered User

To substitute multiple variable by their content in a file

Dear All,

I would like to instantiate a "pattern file" substituting "variable name" by their content.

Saying, we have:

1/ a "pattern file" containing different "variable name", the first character of the "variable name" is "@":

Code:

[x004191a@xsnl11p317a modl]$ cat TPTModl.txt
                              DEFINE OPERATOR FILE_READER_@OBJ_TBLNAME_CD
                              DESCRIPTION 'TERADATA PARALLEL TRANSPORTER DATA CONNECTOR PRODUCER OPERATOR'
                              TYPE DATACONNECTOR PRODUCER
                              SCHEMA SCHEMA_@OBJ_TBLNAME_CD
                              ATTRIBUTES
                            (
                              DirectoryPath                = '@DirectoryPath'
                            , ArchiveDirectoryPath         = '@ArchiveDirectoryPath'
                            , FileName                     = '@OBJFLOWPARM_FILEPATTERNDEFN_CD'
                            , Format                       = 'DELIMITED'
                            , TextDelimiter                = '@OBJFLOWPARM_FILETEXTDELIMITER_CD'
                            , EnableScan                   = 'Y'
                            , IndicatorMode                = 'N'
                            , TrimTrailingBlanks           = 'Y'
                            , TrimLeadingBlanks            = 'Y'
                            , OpenMode                     = 'Read'
                            );

2/ a variable with the list of the "variable name" with their value:

Code:

[x004191a@xsnl11p317a tmp]$ echo "$var"
@OBJ_DBNAME_CD:ABCD
@OBJ_TBLNAME_CD:EFGH
@OBJFLOWPARM_FILEPATTERNDEFN_CD:*_VERSFLDR.csv
@OBJFLOWPARM_FILETEXTDELIMITER_CD:$$

How would it be possible to produce an output file from the pattern input file with all the replacement done ?

Thanks a lot for your help and kind attention,

Didier.

dae

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zegrep

ZGREP(1)                                                      General Commands Manual                                                     ZGREP(1)

NAME

       zgrep - search possibly compressed files for a regular expression

SYNOPSIS

       zgrep [ grep_options ] [ -e ] pattern filename...

DESCRIPTION

       Zgrep  invokes  grep  on  compressed  or  gzipped  files.   These  grep  options  will  cause  zgrep  to  terminate  with  an  error  code:
       (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*).  All other options specified are passed directly to grep.  If no file is specified,  then  the
       standard input is decompressed if necessary and fed to grep.  Otherwise the given files are uncompressed if necessary and fed to grep.

       If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.

EXIT CODE

       2 - An option that is not supported was specified.

AUTHOR

       Charles Levert (charles@comm.polymtl.ca)

SEE ALSO

       grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)

                                                                                                                                          ZGREP(1)

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