how to make a line BLINKING in output and also how to increase font size in output
suppose in run a.sh script
inside echo "hello world "
i want that this should blink in the output and also
the font size of hello world should be big ..
could you please help me out in this (3 Replies)
Hi Guys,
I am trying to convert a file which has a row based output to a column based output. My original file looks like this:
1
2
3
4
5
6
1
2
3
1
2
3 (8 Replies)
So, the beginning of my script will cat & grep a file with the output directed to a new file. The data I have in this file needs to be parsed, read and evaluated.
Basically, I need to identify the latest date/time stamp and then calculate whether or not it is within 15 minutes of the current... (1 Reply)
Hi Guys,
Anyone who knows how to compare the current date with the a file containing a date, say for example I have a file that looks like this:
Command was launched from partition 0.
------------------------------------------------
Executing command in server server6
Fri Dec 16... (7 Replies)
Hello,
I was wondering if anyone knows a faster way to search and compare strings and dates from 2 files?
I'm currently using "for loop" but seems sluggish as i have to cycle through 10 directories with 10 files each containing thousands of lines.
Given:
-10 directories
-10 files... (4 Replies)
Hi Guys,
I have a file with following content
From 20121014 : To 20121014
Number of days : 1
1234
1245
1246
1111
Everyday i run my script i want to modify "To" date on the first line with current date. I have set the current date in script as
RUN_DATE=`date -u +%Y%m%d`
So i want... (9 Replies)
Hello,
I have a file like this:
2012112920121130
12345620121130msABowwiqiq
34477420121129amABamauee
e7748420121130ehABeheheei
in case the content of the file has the date of yesterday within the lines containing pattern AB this should be replaced by the current date. But if I use... (3 Replies)
Sed command to replace a line in a file using line number from the output of a pipe.
Is it possible to replace a whole line piped from someother command into a file at paritcular line...
here is some basic execution flow..
the line number is 412
lineNo=412
Now i have a line... (1 Reply)
I have a test file with the following format, It contains the username_date when the user was locked from the database.
$ cat lockedusers.txt
TEST1_21062016
TEST2_02122015
TEST3_01032016
TEST4_01042016
I'm writing a ksh script and faced with this difficult scenario for my... (11 Replies)
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)