I have no idea why I can't get this to work, if anybody can help i would appreciate it.
#!/bin/bash
x=`cat counter.txt | wc -l`
y= '$x / 7'
printf "%d People have visited this page" $y
:confused: (2 Replies)
I am using egrep to extract numbers from a file and storing them as variables in a script. But I am not able to do any arithmetic operations on the variables using "expr" because it stores them as char and not integers. Here is my code and the error I get. Any help will be appreciated.
#!/bin/sh... (3 Replies)
Hi, All,
I have a file, its content is as follows:
100 150
120 135
140 170
I want to insert a column, its content is determined by the difference between the two values in the same line, if the difference is less than 20, the new value is 1, otherwise is 0.
after the operation, the... (1 Reply)
Hi all,
I would appreciate if anyone knows how to perform adding to date.
As for normal date, i can easily plus with any number.
But when it comes to month end say for example 28 Jun, i need to perform a plus with number 3, it will not return 1 Jul.
Thanks in advance for your help. (4 Replies)
Hi
I have a file with 3 columns. say,
infile:
1 50 68
34 3 23
23 4 56
-------
-------
I want to generate n files from this file using a loop so that 1st column in output file is (column1 of infile/(2*n+2.561))
I am doing like this:
for ((i=1; i<=3; i++))
do
a=`echo... (3 Replies)
I am writing a script in zsh shell, it fetchs a number from a file using the awk command, store it as a variable, which in my case is a small number 0.62000. I want to change this number by multiplying it by 1000 to become 620.0 using the command in the script
var2=$((var1*1000))
trouble is... (2 Replies)
input:
Name|Operation
rec_10|1+2+2-
Output:
rec_10|1
Basically I am trying to calculate the result of "the path" in $3 where the operators follow the number and not preceding them like we normally do:
rec_10: +1+2-2=1
But I realise (I am sure there is a good reason for that) that awk... (7 Replies)
I have to do some arithmetic operation on Field 8 which is calculated by Field 9/Field 7
Suppose i have data like :
0800123456|JAN|2017|JAN|2018|0800123456|0|0.0000|0.00|
0800234567|JAN|2017|JAN|2018|0800234567|4|2.5812|10.32|
0800666666|JAN|2017|JAN|2018|0800666666|2|1.7255|3.45|... (0 Replies)
Discussion started by: pumrao
0 Replies
LEARN ABOUT DEBIAN
io::async::timer::absolute
IO::Async::Timer::Absolute(3pm) User Contributed Perl Documentation IO::Async::Timer::Absolute(3pm)NAME
"IO::Async::Timer::Absolute" - event callback at a fixed future time
SYNOPSIS
use IO::Async::Timer::Absolute;
use POSIX qw( mktime );
use IO::Async::Loop;
my $loop = IO::Async::Loop->new;
my @time = gmtime;
my $timer = IO::Async::Timer::Absolute->new(
time => mktime( 0, 0, 0, $time[4]+1, $time[5], $time[6] ),
on_expire => sub {
print "It's midnight
";
$loop->stop;
},
);
$loop->add( $timer );
$loop->run;
DESCRIPTION
This subclass of IO::Async::Timer implements one-shot events at a fixed time in the future. The object waits for a given timestamp, and
invokes its callback at that point in the future.
For a "Timer" object that waits for a delay relative to the time it is started, see instead IO::Async::Timer::Countdown.
EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters:
on_expire
Invoked when the timer expires.
PARAMETERS
The following named parameters may be passed to "new" or "configure":
on_expire => CODE
CODE reference for the "on_expire" event.
time => NUM
The epoch time at which the timer will expire.
Once constructed, the timer object will need to be added to the "Loop" before it will work.
Unlike other timers, it does not make sense to "start" this object, because its expiry time is absolute, and not relative to the time it is
started.
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2012-10-24 IO::Async::Timer::Absolute(3pm)