hi,
how do i get the last day of the current date or a given date using unix.
for e.g. if i run the command/script on 1st feb 2002 i should get 28 th feb 2002.
thanks !!
AnkuR. (3 Replies)
hi guys, i've got a simple one..
date_time="`date '+%Y-%m-%d %H:%M:%S'`" gives me the system's date and time...
which my script will use this variable to run the data on this date...
my question is... if now, i want to run the script for data's that are like 6 months back...
how can i... (1 Reply)
I know there are some posts on getting the time with milliseconds included and I realize unix may not be the best on this.
I have seem some posts where its advised to install the GNU date.
Any one know where I can download this as I am struggling to find it.
Alternatively - if you have... (5 Replies)
How could I get a date's day of the week (ie Sunday) without using the date -d command?
So if a date was specified, it would give me the day of the week.
The date -d command looks something like this
date -d $inputdate | cut -c 1-3
the only problem with that statement is that it won't... (2 Replies)
I have been out of the UNIX World for a number of years and none of my reference books seem to be helping e with this seemingly simple question. How can I manipulate the below command to reflect the previous day and not the current date?
the command is:
elm -s “SAP prs for `date... (4 Replies)
Should work in any shell, but requires GNU date, although GNU date seems only to be happy for input dates between 1902 and 2037, inclusive (49673 days).
Assume $a and $b hold two dates, e.g.
set a=2010-03-27
set b=2010-04-04
Marginally faster:
iterator: seq -f "$a +%1.0f days" 1 50000 |... (0 Replies)
Hello everybody,
Currently I'm learning how to build projects (C programming) with GNU make. I have a problem with one Makefile and I would appreciate if you could kindly give me a hand. Here is the environment:
OS: Redhat linux 5
compiler: gcc (GCC) 4.1.2 20080704 (Red Hat 4.1.2-44)... (2 Replies)
Dear all,
This should be simple but I cannot figure it out despite reading all the man pages. Could someone please help me translate this code (GNU date) to one that can be read by BSD date?:
myDate=$(date -d "$h -$l days" +%Y/%m/%d),
where h is a variable of the form DD/MM/YYYY, and l is... (3 Replies)
It's easy as pie to get the date minus one day on opensolaris:
date -d "-1 day" +"%Y%m%d"run this command on our crappy Solaris 10 machines however (which I'm guessing doesn't have GNU date running on it) and you get:
date: illegal option -- d
date: illegal option -- 1
date: illegal option --... (5 Replies)
So as I write this today is two days after the clocks go back here in the UK. I have a script that worked last week. Yesterday it developed a bug. I eventually found the culprit is Gnu Date.
$ lsb_release -a
No LSB modules are available.
Distributor ID: Ubuntu
Description: Ubuntu 16.04.5 LTS... (10 Replies)
Discussion started by: apmcd47
10 Replies
LEARN ABOUT DEBIAN
unparse_time
PARSE_TIME(3) BSD Library Functions Manual PARSE_TIME(3)NAME
parse_time, print_time_table, unparse_time, unparse_time_approx, -- parse and unparse time intervals
LIBRARY
The roken library (libroken, -lroken)
SYNOPSIS
#include <parse_time.h>
int
parse_time(const char *timespec, const char *def_unit);
void
print_time_table(FILE *f);
size_t
unparse_time(int seconds, char *buf, size_t len);
size_t
unparse_time_approx(int seconds, char *buf, size_t len);
DESCRIPTION
The parse_time() function converts a the period of time specified in into a number of seconds. The timespec can be any number of <number
unit> pairs separated by comma and whitespace. The number can be negative. Number without explicit units are taken as being def_unit.
The unparse_time() and unparse_time_approx() does the opposite of parse_time(), that is they take a number of seconds and express that as
human readable string. unparse_time produces an exact time, while unparse_time_approx restricts the result to only include one units.
print_time_table() prints a descriptive list of available units on the passed file descriptor.
The possible units include:
second, s
minute, m
hour, h
day
week seven days
month 30 days
year 365 days
Units names can be arbitrarily abbreviated (as long as they are unique).
RETURN VALUES
parse_time() returns the number of seconds that represents the expression in timespec or -1 on error. unparse_time() and
unparse_time_approx() return the number of characters written to buf. if the return value is greater than or equal to the len argument, the
string was too short and some of the printed characters were discarded.
EXAMPLES
#include <stdio.h>
#include <parse_time.h>
int
main(int argc, char **argv)
{
int i;
int result;
char buf[128];
print_time_table(stdout);
for (i = 1; i < argc; i++) {
result = parse_time(argv[i], "second");
if(result == -1) {
fprintf(stderr, "%s: parse error
", argv[i]);
continue;
}
printf("--
");
printf("parse_time = %d
", result);
unparse_time(result, buf, sizeof(buf));
printf("unparse_time = %s
", buf);
unparse_time_approx(result, buf, sizeof(buf));
printf("unparse_time_approx = %s
", buf);
}
return 0;
}
$ ./a.out "1 minute 30 seconds" "90 s" "1 y -1 s"
1 year = 365 days
1 month = 30 days
1 week = 7 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
1 second
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 90
unparse_time = 1 minute 30 seconds
unparse_time_approx = 1 minute
--
parse_time = 31535999
unparse_time = 12 months 4 days 23 hours 59 minutes 59 seconds
unparse_time_approx = 12 months
BUGS
Since parse_time() returns -1 on error there is no way to parse "minus one second". Currently "s" at the end of units is ignored. This is a
hack for English plural forms. If these functions are ever localised, this scheme will have to change.
HEIMDAL October 31, 2004 HEIMDAL