Hello, date --date '-60 min ago' +'%Y-%m-%d %H:%M:%S,%3N'
Above command gives the date and time minus 60 minutes
but the problem i am facing is, i do not want to hardcode the value 60
it is stored in a variable var=60
now if i run below command , i get error date --date '-$var min ago' +'%Y-%m-%d %H:%M:%S,%3N'
date: invalid date `-$var min ago'
Please suggest
Hello Ramneekgupta91,
I think you should remove - from command -60 min ago so only it will give time and date before 60 mins else it is giving 60 mins after time(you could take it as a maths concept of -ve * -ve = +ve kind of). Because you are already using keyword ago and then you are mentioning value -60 mins ago, so it will print value after 60 mins.
Here is what is the difference between -60 mins ago and 60 mins ago.
Current time:
Using -60 mins ago:
Using only 60 mins ago:
Now for taking values from a variable following may help you in same.
Thanks,
R. Singh
These 4 Users Gave Thanks to RavinderSingh13 For This Post:
Hi All,
I want to find out the time before 30 minutes. I am able to do with in hours limit.
date
Fri Aug 21 06:50:00 BST 2009
TZ=CST+1 date
Fri Aug 21 04:50:02 CST 2009
Can any one please help me (6 Replies)
Hi
i want to print the time of a process in hours only..(or) in minutes only.Is there anyway to print the process such like that
when i give the commnand like following
#ps -eo pid,time
PID TIME
412 01:49:32
481 00:03
it shows in HH:MM:SS format:
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i have the time 20100421043335 in format (date +%Y%m%d%H%M%S),and i want to be able to get the previous time 2 minutes ago,which is
20100421043135 (9 Replies)
In Redhat it is easy....
date --date="60 minutes ago"
How do you do this in Solaris?
I got creative and got the epoch time but had problems..
EPOCHTIME=`truss date 2>&1 | grep "time()" | awk '{print $3 - 900}'`
echo $EPOCHTIME
TIME=`perl -e 'print scalar(localtime("$EPOCHTIME")),... (5 Replies)
Hi,
I need to subtract 5 minutes from the date. Example
$date +"%Y-%m-%d-%H.%M.%S" displays 2014-06-26-06.06.38
I want to show it as 2014-06-26-06.01.38 (5 mins are subtracted from date)
Any help would be appreciated. I am currently on AIX version 6.1
-Vrushank (10 Replies)
Hi Folks,
I have a text file that has only time in the format HH:MM:SS like seen below.
21:36:17
23:52:08
I need to find the difference in minutes alone from this text file so the result would be 136.
Thanks
Jay (11 Replies)
Hello all,
Info:
System RedHat 7.5
I need to create a script that based on the creation time,
if the file is older then 5 minutes then execute some stuff, if not exit.
I thought to get the creation time and minutes like this.
CreationTime=$(stat -c %y /tmp/test.log | awk -F" " '{ print... (3 Replies)