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Full Discussion: Looping through input/output
Top Forums UNIX for Beginners Questions & Answers Looping through input/output Post 302979882 by zajtat on Saturday 20th of August 2016 08:30:52 PM
Old 08-20-2016
I'm sorry my explanations were not clear.

The executable command takes the columns of file specified in argument 1 (infile1) and adds them to the file specified in argument 2 (infile2). It creates a new file that starts with columns from infile2, followed by columns from infile1. So, the first command line is:

combining.executable infile1 infile2 > outfile1

This will take infile2 as the basis and add columns to it from infile1. The outfile1 will start with columns from infile2 and finish with columns from infile1.

The we run the following command:

combining.executable infile3 outfile1 > outfile2

This will take the columns from the file specified as argument 1 (infile3) and add them to the file specified in the argument 2 (outfile1). It is the same procedure as in step1, so the program does the same thing, nothing changes. The resulting outfile2 will start with columns from outfile1 and finish with columns from infile3. So, all 3 files are combined and nothing is deleted/replaced.

For the next step, we'll need outfile2 and infile4. So, we can delete the outfile1 as its info is now in outfile2. And so on...

This is your next question:

What is the format of the real names of your input files? (Please show us the actual names of your 1st input file and your last input file.)

The answer: the files are simple text files, here is the name of my first input file:

9464294024_R01C01header

and the last file name is:

9479475073_R12C02header

here is a small subsample of the files:

Code:
9464294024_R01C01header  9477371149_R12C02header  9477871078_R06C01header  9477875165_R03C01header  9477885102_R05C01header  9479475073_R10C02header
9464294024_R01C02header  9477371157_R01C01header  9477871078_R06C02header  9477875165_R03C02header  9477885102_R05C02header  9479475073_R11C01header

Next question: And, is the number of input files a constant?

I'm not sure I understand this question. There is exactly 5427 files than need to be combined into one.

Next question: And, what name do you really want for your output file?

The name of the output file does not really matter for me. It can be anything as long as it contains the columns of all the 5427 files combined into one text file.

Many thanks!
Last edited by Don Cragun; 08-20-2016 at 09:53 PM.. Reason: Change ICODE tags to CODE tags for long data lines.
 

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LEARN ABOUT MOJAVE

colrm

COLRM(1)						    BSD General Commands Manual 						  COLRM(1)

NAME

     colrm -- remove columns from a file

SYNOPSIS

     colrm [start [stop]]

DESCRIPTION

     The colrm utility removes selected columns from the lines of a file.  A column is defined as a single character in a line.  Input is read
     from the standard input.  Output is written to the standard output.

     If only the start column is specified, columns numbered less than the start column will be written.  If both start and stop columns are spec-
     ified, columns numbered less than the start column or greater than the stop column will be written.  Column numbering starts with one, not
     zero.

     Tab characters increment the column count to the next multiple of eight.  Backspace characters decrement the column count by one.

ENVIRONMENT

     The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).

EXIT STATUS

     The colrm utility exits 0 on success, and >0 if an error occurs.

SEE ALSO

     awk(1), column(1), cut(1), paste(1)

HISTORY

     The colrm command appeared in 3.0BSD.

BSD
								  August 4, 2004							       BSD
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