i tried to extract the date using the below code but not able to,can you please check
Code:
#Script for copying files from src to dest based on same date and time
#!/bin/bash
#Script Variables
SPATH="/remote/home/folder1"
DPATH="/remote/home/folder2"
SUFFIX_ARG="*.txt"
ACTION_TIME=`date +'%Y%m%d' "%H:%M:%S:"`
echo "${ACTION_TIME} Starting copy task"
find ${SPATH} -type f -name "${SUFFIX_ARG}" -print | while read path
do
FN="${path##*/}" #extract the file name from the path
temp=${FN#*_}
date=${temp%.txt.pgp} # trying to get the date alone
echo "this is the file name"$FN
ACTION_TIME=`date +"%Y%m%d %T"`
if [ -e "${DPATH}/${FN}" ] #if the destination file exists, skip it
then
echo "${ACTION_TIME} Skipped: File ${DPATH}/${FN} already exist"
else
cp "$path" "${DPATH}/${FN} ${ACTION_TIME}"
ACTION_TIME=`date +"['%y%m%d' %T]:"`
echo "${ACTION_TIME} Copy ${FN} to ${DPATH} Complete"
fi
echo "done copy"
done
Moderator's Comments:
Please use CODE tags as required by forum rules!
Last edited by RudiC; 08-18-2016 at 12:28 PM..
Reason: Added/corrected CODE tags.
Hi Friends,
Can any one help with this:
I have a huge file with the format as
A SAM 4637
B DEPT1 4758 MILAN
A SMITH 46585
B DEPT2 5385 HARRYIS
B SAMUL 63547 GEORGE
B DANIEL 899 BOISE
A FRES 736 74638
I have to read this file and write only the records that starts with "B" only
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Hi,
I need help with this-
input.txt :
L B white
X Y white
A B brown
M Y black
Read this input file and if 3rd column is "white", then add specific lines to another file insert.txt.
If 3rd column is brown, add different set of lines to insert.txt, and so on.
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HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
Hi Guys,
I have certain files in my directory which gets appended with dates something like this
T1_aug17.txt
T1_Aug17.txt
T1_Sep17.txt
config.txt
T1
T2
my code:
curr_date=`date -d "$date" +%Y-%m-%d`
path=mydir
for file in `cat config.txt`
do
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Hi All,
I am having a job and I need to send email when the job is running. On any other case (success,fail) I don't needed to send email. I check with BMC they told they dont have that in the version I am using.
So I created a dependent job and grepped for the status and sent email. My... (1 Reply)
Discussion started by: arunkumar_mca
1 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)
08-18-2016
