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Full Discussion: Problem with loop
Top Forums Shell Programming and Scripting Problem with loop Post 302978393 by Board27 on Friday 29th of July 2016 03:00:02 PM
Old 07-29-2016
Problem with loop

Hi all,
a problem with a loop. Imagine it starts with

Code:
var1="$(cat txtif.out )"

Code:
while  [ $var1 = x ]
  do
  echo file1
  echo file2
  echo y > txtif.out 
  if [ $var1 = y ]
  then
    break
  fi
done

exit  0

the problem is that if the file is changing during the loop seems to continue as it reads "x" state, while in the loop it should change to y and break, instead it returns from the beginnig.

Any idea how to break the loop?

Thanks!

Last edited by Board27; 07-29-2016 at 05:01 PM..
 

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IO::Async::Signal(3pm)					User Contributed Perl Documentation				    IO::Async::Signal(3pm)

NAME
"IO::Async::Signal" - event callback on receipt of a POSIX signal SYNOPSIS
use IO::Async::Signal; use IO::Async::Loop; my $loop = IO::Async::Loop->new; my $signal = IO::Async::Signal->new( name => "HUP", on_receipt => sub { print "I caught SIGHUP "; }, ); $loop->add( $signal ); $loop->run; DESCRIPTION
This subclass of IO::Async::Notifier invokes its callback when a particular POSIX signal is received. Multiple objects can be added to a "Loop" that all watch for the same signal. The callback functions will all be invoked, in no particular order. EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters: on_receipt Invoked when the signal is received. PARAMETERS
The following named parameters may be passed to "new" or "configure": name => STRING The name of the signal to watch. This should be a bare name like "TERM". Can only be given at construction time. on_receipt => CODE CODE reference for the "on_receipt" event. Once constructed, the "Signal" will need to be added to the "Loop" before it will work. AUTHOR
Paul Evans <leonerd@leonerd.org.uk> perl v5.14.2 2012-10-24 IO::Async::Signal(3pm)
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