Passing variable value in a function to be used by another function Post: 302975986

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May i please know why is it printing the script name for $0 when i pass those parameters to function. #!/bin/bash -x usage() { echo "In Usage Function" echo $0 echo $1 echo $2 } echo "printing first time" echo $0 echo $1 echo $2 usage $0 $1 $2 Output:

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LEARN ABOUT DEBIAN

uligo

uligo(6)							   Games Manual 							  uligo(6)

NAME

       uligo - tsumego (go problems) practice tool

SYNOPSIS

       uligo

DESCRIPTION

       To  get	stronger  at  go, it is essential to develop one's reading ability. That is why professionals recommend to study life and death or
       tesuji problems.  uliGo is a program that allows you to do that: basically, the computer displays a problem, and asks for the  answer.  You
       enter the first move, the computer responds, and so on until you reach the final solution or enter a wrong move.

USAGE

       The  basic  operation of uliGo is simple. Click the right arrow to view a problem, and then click where you think the right answer is.  The
       Documentation item in the Help menu contains the full documentation for uliGo, such as configuring the timer or the order the  tsumego  are
       displayed in.

       By default, problems are presented in random order, with the colors and orientation of the problem randomly chosen.

FILES

       ~/.uligo
	      This directory stores information about how many problems you've solved, and SGF files you've downloaded yourself.

AUTHOR

       Ulrich  Goertz  <uligo@g0ertz.de>  is the author of uliGo. Joe Wreschnig <piman@debian.org> wrote this manual page for the Debian operating
       system, but it may be used by others.

SEE ALSO

       The uliGo website at http://www.u-go.net/uligo/ contains more (unclearly licensed) problems sets that cannot be included  with  the  Debian
       package.

								 April 25th, 2003							  uligo(6)

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passing a variable inside a variable to a function

Discussion started by: KingVikram