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Full Discussion: File updation on matching key
Top Forums UNIX for Dummies Questions & Answers File updation on matching key Post 302975204 by PRAMOD 96 on Thursday 9th of June 2016 11:12:49 AM
Old 06-09-2016
Hi Rudic,

Thanks for your update on this. But it is not working for my case. And one more thing I have not got your code
Code:
awk 'NR == FNR {SUM[$3]+=$7+$9; next} {sub (FS $8 FS, FS sprintf ("%06d", SUM[$3]/2) FS)}1' file file

Here I have not got "file" means which file ? I have used your code for my input but it not worked.
I brief u about input and output . Input as below
Code:
RRD       0Z9He4r000000Lk 200741     00120160129    STMT151117055527001            0000 1 000000 000001
RRD       0Z9He4r00001Gnl 200745     00120160129    STMT151117055527001            0000 1 000000 000001
RRD       0Z9He4r00001IPC 3025339512 33820160129    STMT151117055527001            0000 1 000000 000005
RRD       0Z9He4r00000pTO 4025339512 33820160129    STMT151117055527001            0000 0 000000 000002
RRD       0Z9He4r000001xE 5025339518 33820160129    STMT151117055527001            0000 0 000000 000004
RRD       0Z9He4r00000SHB 7025339518 33820160129    STMT151117055527001            0000 1 000000 000003
RRD       0Z9He4r00000XXX 7025339518 33823333333    STMT151117055527001            0000 3 000000 000002

in the Input given column 3 is the key column. consider row 1
Code:
RRD       0Z9He4r000000Lk 200741     00120160129    STMT151117055527001            0000 1 000000 000001

Here key is 200741. So search for 200741 in remaining rows of column 3. Here is no other key like 200741. So here calculation will be like
((7th column value + 9th column value)of row 1)/2 ie (1+1)/2=1. So update column 8 of row 1 with value 000001.


Explanation 2 : Consider row 6
Code:
RRD       0Z9He4r00000SHB 7025339518 33820160129    STMT151117055527001            0000 1 000000 000003

here key is 7025339518. So search for 7025339518 in remaining rows of column 3. Here you will find key 7025339518 in row 7 as well. so for this the calculation
will be like ((7th column value + 9th column value)of row 6 + (7th column value + 9th column value)of row 7)/2 => ((1+3)+(3+2))/2=5. So update column 8 of row 6
and 7 with value 000005


So Expected output for above result is :

Code:
RRD       0Z9JS1l000000Lk 200741     00120160129    STMT151117055527001            0000 1 000001 000001
RRD       0Z9JS1l00001Gnl 200745     00120160129    STMT151117055527001            0000 1 000001 000001
RRD       0Z9JS1l000001xE 5025339518 33820160129    STMT151117055527001            0000 0 000002 000004
RRD       0Z9JS1l00000pTO 4025339512 33820160129    STMT151117055527001            0000 0 000001 000002
RRD       0Z9JS1l00001IPC 3025339512 33820160129    STMT151117055527001            0000 1 000003 000005
RRD       0Z9JS1l00000SHB 7025339518 33820160129    STMT151117055527001            0000 1 000005 000003
RRD       0Z9He4r00000XXX 7025339518 33823333333    STMT151117055527001            0000 3 000005 000002

Please update code accordingly..


---------- Post updated at 08:42 PM ---------- Previous update was at 08:00 PM ----------

Hi Ridic,
your code worked. Smilie
Code:
awk 'NR == FNR {SUM[$3]+=$7+$9; next} {sub (FS $8 FS, FS sprintf ("%06d", SUM[$3]/2) FS)}1' $input_file $input_file

for below input :
Code:
RRD       0Z9He4r000000Lk 200741     00120160129    STMT151117055527001            0000 1 000000 000001
RRD       0Z9He4r00001Gnl 200745     00120160129    STMT151117055527001            0000 1 000000 000001
RRD       0Z9He4r00001IPC 3025339512 33820160129    STMT151117055527001            0000 1 000000 000005
RRD       0Z9He4r00000pTO 4025339512 33820160129    STMT151117055527001            0000 0 000000 000002
RRD       0Z9He4r000001xE 5025339518 33820160129    STMT151117055527001            0000 0 000000 000004
RRD       0Z9He4r00000SHB 7025339518 33820160129    STMT151117055527001            0000 1 000000 000003
RRD       0Z9He4r00000XXX 7025339518 33823333333    STMT151117055527001            0000 3 000000 000002

output as below :
Code:
RRD       0Z9He4r000000Lk 200741     00120160129    STMT151117055527001            0000 1 000001 000001
RRD       0Z9He4r00001Gnl 200745     00120160129    STMT151117055527001            0000 1 000001 000001
RRD       0Z9He4r00001IPC 3025339512 33820160129    STMT151117055527001            0000 1 000003 000005
RRD       0Z9He4r00000pTO 4025339512 33820160129    STMT151117055527001            0000 0 000001 000002
RRD       0Z9He4r000001xE 5025339518 33820160129    STMT151117055527001            0000 0 000002 000004
RRD       0Z9He4r00000SHB 7025339518 33820160129    STMT151117055527001            0000 1 000004 000003
RRD       0Z9He4r00000XXX 7025339518 33823333333    STMT151117055527001            0000 3 000004 000002

Just one minor updation needed. If the division result is decimal value ie for row 6 and 7 it is 4.5 but it shows it as 4 . Can we make it as round value as 5. ie if result is 6.5 then it should be display 7
Last edited by RudiC; 06-09-2016 at 12:25 PM.. Reason: Removed unnecessary quote tags.
 

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