The actual requirement I have is to take the timestamp (file name here can be ignored), append it to all rows in the file so that it can loaded in database through sqlldr.
Once I extract the timestamp of the file in UNIX and pass it in one variable like $1 then I can further use the below command to make a new data file which I will load.
Code:
sed -e 's/$/ May 04 09:02/' summary_file.sql > Data_file.sql
I hope I am clear now.
I tried your suggested command :
File content is:-
***************
Code:
-rw-r----- 1 owner owner 976 May 04 09:02 summary_file.sql
Suppose I have a unix file which contain a lost of 60 files like
filename1
filename2
...
..
...
filename60
I want to write a unix script that will pick up first 10 files in first run
10-20 files in 2 run
20-30 files in 3 run
30-40 files in 4 run
40-50 files in 5 run
50-60 files in 6... (1 Reply)
I have a requirement of checking the current system time and performing certain actions in a shell script. example:
if the current system time is greater than 1400 hrs, then perform step 1,2,3
if the current system time is greater than 1000 hrs, then perform step 1,2
if the current system time... (2 Replies)
i am using function
gethrtime() in sun solaries
to get the time independent of the system time.Problem with this function is if we restart the system time will change to '0'.is there any other way to resolve this problem.
thanks & regards
suresh (3 Replies)
Hi All
I am stuck in a problem and wants help
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Hi ,
Can anyone help me how do perform below requirement in unix.
Step1:we will receive multiple files weekly with same name(as below) in a folder(In folder we will have other files also def.dat,ghf.dat)
Filenames:
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06-08-2016
