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Shell Programming and Scripting
Strip the first record off a file and isolate fields off of it
Post 302974241 by jclanc8 on Thursday 26th of May 2016 07:43:52 PM
05-26-2016
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Hi,
In a script I have to check that input text files with a variable number of tab delimited fields have at least n fields and no more than m fields. Records are delimited by <CR> and <LF>.
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Hi,
I'm trying this command - but get this error.
Do you guys have any workaround for this?
cat tf|sed 's/{//g'|sed 's/,//g'|awk '{for (i=1;i<=NF;i++) {if ($i == "OPTIME") {k = i + 2; print $i,$k}}}'
awk: record `2005 Jul 28 17:35:29...' has too many fields
record number 15
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Hi all,
I have an input file with no delimiter. Let us say the file is abc.txt having values for fields namely, EmpNumEnameDesigSalDept. Ofcourse the file has got several records. Every field has got a fixed start and end position.
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I was wondering if there was a way to modify a tab delimited text file, up to 185,000 lines long by adding a repeated field to a block of 20 data , then repeat the process until the file is processed.
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5. Shell Programming and Scripting
Dear All ,
I have the query
cat temp.txt
|28-07-1997|IF_LEG_DCCT|TOV JV sdfsdfdsfdsfdsCLOSED* KIEV|381015280
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:confused:
Hi Friends,
In the record below i have to make changes in the fields by putting the values stored in the temporary variables, x, y, z, p, q, r:
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Hi,
i want to generate print statement using awk.
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my record is as shown below filename
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8. Shell Programming and Scripting
Sample file record :
"20130617003","2013-06-18T07:00:03","OUTWARD","01001011","TEST PLC","","HFX834346364364","20130617","10","DUM87534758","","1.28","826","020201","65879278","","","","","","010101","56789","DUMMY... (3 Replies)
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